Question

The cost of 2 tables and 3 chairs is $705. If the table costs $40 more than the chair, how much does a table cost?

Answer 1

Answer:

Step-by-step explanation:

2 tables and 3 chairs is $705

Let t stand for table and c stand for chair

3c + 2t = 705

We are told that the table costs $40 more than the chair, so t = c + 40

Now we can insert this into the equation

3c + 2(c + 40) = 705

The next step is to distribute the 2

3c + 2c + 80 = 705

Then combine like terms

5c + 80 = 705

To get the variable by itself, you have to subtract the 80 from both sides.

5c = 705 - 80

5c = 625

This means that 5 chairs costs $625.

Divided both sides by 5 to isolate the variable

c = 625/5

c = 125

Great, now you know the cost of one chair, $125!

The question is asking how much a table costs, and we know that a table costs $40 more than a chair.

A table costs $125 + $40

A table costs $165

Hope this helps! =)