Answer:
2.401 * 10^3
Step-by-step explanation:
put -7 to the fourth power and then use scientific notation rules
Answer:
Step-by-step explanation:
The motorist drove at a distance of 90km at a constant speed for the first 40km, and then 20 km/hr faster for the rest of the journey.
The whole journey took him 1hr.
Let S denotes the average speed (in km/hr) for the first 40 km.
Hence we get the following relation,
40/S + (90 - 40)/(S + 20) = 1
or 50/(S + 20) = 1 - 40/S = (S - 40)/S
or (S + 20)(S - 40) = 50S or S^2 - 70S - 800 = 0 or (S - 80)(S + 10) = 0
or S = 80 (km/hr) [Ans]
[S cannot be negative value]
12)
First of all, you need to know that profit is the difference between selling price and cost price. In this problem, profit is equal to the markup. Total profit is equal to the profit on each car multiplied by the number of cars sold.
The profit on each car is 2000 -400n, where n is defined in the problem statement as the number of markdowns (of $400).
The number of cars sold is 20 +6n. (Starting at 20, increasing by 6 for every markdown.)
The total monthly profit is the product of these binomials.
.. P(n) = (2000 -400n)*(20 +6n)
.. P(n) = -2400n^2 +4000n +40,000 . . . . . . selection C
13)
Matching functions to data points is often just a matter of trying them to see which fits. The first two function both match points (0, 2) and (1, 6). Functions C and D fail to match (1, 6).
Only the second function matches (2, 18).
The appropriate choice is
.. B. y = 2(3)^x
Answer:
Step-by-step explanation:
We are given that A rose garden can be planted for $4000.
The marginal cost of growing a rose is estimated to $0.30,
Let x be the number of roses
So, Marginal cost of growing x roses = 
Total cost = 
So, Cost function : ---A
Now we are given that the total revenue from selling 500 roses is estimated to $875
So, Marginal revenue = 
Marginal revenue = 
Marginal revenue = 
Marginal revenue for x roses = 
So, Revenue function = ----B
Profit = Revenue - Cost
---C
Now Plot A , B and C on Graph
-- Green
-- Purple
--- Black
Refer the attached graph
