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melamori03 [73]
3 years ago
10

Simplify the expression below. (-3x^2 +2x -4) (4x^2 +5x -9)?

Mathematics
1 answer:
Veronika [31]3 years ago
6 0
The answer is X^2+7x-13
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CAN YOU PLEASE HELP ME WITH THIS PROBLEM???
ozzi

Answer:

Step-by-step explanation:

tan \ 50 =\dfrac{opposite \ side}{adjacent side}\\\\\\1.19=\dfrac{21}{MD}\\\\\\1.19*MD=21\\\\MD = \dfrac{21}{1.19}\\\\\\MD = 17.65

4 0
2 years ago
Find the length of arc XW. Round your answer to the nearest hundredth.
Luda [366]

Answer:

15.08 m

Step-by-step explanation:

The angle XZW :

XZW + 108° = 180°

XZW = 180° - 108°

XZW = 72°

Length of an arc = θ / 360 * πd

d = diameter = XV = 24

Length of arc XW = (72/360) * π * 24

Length of arc XW = 15.0796

Length of XW = 15.08 m

4 0
3 years ago
Which of these functions has the same graph but shifted to the left?
kogti [31]

Step-by-step explanation:

the second and the 6th options keep the same graph but shift it to the left.

the other options :

the first option changes the graph (the factor -2 stretched and flips the graph).

the third and the 5th options shift the graph up and down. but not to the left.

the 4th option shifts it to the right.

when you add a constant inside the x terms, you shift to the left.

when you subtract a constant inside the x terms, you shift to the right.

e.g. when having f(x+2), then everything, that should happen at x+2 happens already at x. 2 units earlier, and therefore a shift to the left.

in the other direction, f(x-2) makes everything that should have happened at x-2 happen finally at x. so, everything shifts 2 units to the right.

6 0
2 years ago
I need help like asap thank youuu
zlopas [31]

CD = √50

....................

....................

7 0
2 years ago
Using the Rational Root Theorem, what are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x – 12?
igomit [66]

Answer:

Option 1 is correct.

Step-by-step explanation:

The given polynomial is

f(x)=20x^4+x^3+8x^2+x-12

we have to find  all the rational roots of the polynomial f(x)

The Rational Root Theorem states that the all possible roots of a polynomial are in the form of a rational number i.e in the form of \frac{p}{q}

where p is a factor of constant term and q is the factor of coefficient of leading term.

In the given polynomial the constant is -12 and the leading coefficient is 20.

\text{All possible factor of -12 are }\pm1,\pm2, \pm3, \pm4,\pm6,\pm12

\text{All possible factor of 20 are }\pm1,\pm2,\pm4,\pm5,\pm10,\pm20

So, the all possible rational roots of the given polynomial are,

\pm1,\pm2, \pm3, \pm4,\pm6,\pm12,\pm\frac{1}{2},\pm\frac{3}{2},\pm\frac{1}{4},\pm\frac{3}{4},\pm\frac{1}{10},\pm\frac{1}{5},\pm\frac{3}{5},\pm\frac{3}{10},\pm\frac{2}{5},\pm\frac{6}{5},\pm\frac{1}{20},\pm\frac{3}{20},\pm\frac{4}{5},\pm\frac{12}{5}

Now, the rational roots of polynomial satisfy the given polynomial

f(-\frac{4}{5})=20(-\frac{4}{5})^4+(-\frac{4}{5})^3+8(-\frac{4}{5})^2-\frac{4}{5}-12=\frac{256}{625}\times 20-\frac{64}{125}+\frac{128}{125}-\frac{4}{5}-12

=\frac{1024}{125}-\frac{64}{125}+\frac{128}{25}-\frac{4}{5}-12

=\frac{960}{125}+\frac{128}{25}-\frac{4}{5}-12=12-12=0

Hence, rational root.

f(\frac{3}{4})=20(\frac{3}{4})^4+(\frac{3}{4})^3+8(\frac{3}{4})^2+\frac{3}{4}-12=\frac{405}{64}+\frac{27}{64}+\frac{9}{2}+\frac{3}{4}-12=0

rational root

f(1)=20(1)^4+(1)^3+8(1)^2+1-12=20+1+8-11=18\neq 0

not a rational root.

hence, option 1 is correct

8 0
3 years ago
Read 2 more answers
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