Given parameters:
Weight of hydrated sample = 20g
Temperature = 250°C
Weight after cooling = 16.5g
Unknown:
Weight of water lost from the sample = ?
Solution:
The weight of water lost from the sample;
Weight of water lost = Weight of hydrated sample - Weight of dry sample
Weight of water lost = 20g - 16.5g = 3.5g
% of water in the sample = 
Input parameters solve;
= 
=17.5%
The chemical reaction is:
<span>SO2Cl2 </span>⇔<span> SO2+ Cl2
This shows that the forward reaction the compound is decomposed to smaller compounds and the backward reaction the larger compound is produced. Adding more chlorine to the mixture when in equilibrium, will shift the equilibrium to the left forming the larger compound.</span>
Explanation:
First, we will calculate the molar mass of 
as follows.
Molar mass of = 
= 78 g/mol
So, when 2 mol of 
burns, then heat produced = 6542 KJ
Hence, this means that 2 molecules of 
are equal to 
of burns, heat produced = 6542 KJ
Therefore, heat produced by burning 5.5 g of =
= 228.97 kJ
= 228970 J (as 1 kJ = 1000 J)
It if given that for water, m = 5691 g
And, we know that specific heat capacity of water is 4.186 
.
As, Q = 
228970 J = 
Thus, we can conclude that the final temperature of the water is 
.
Answer:
Ductility
Explanation:
Ductility is the ability of a metal to be converted into a thin wire without getting break and loosing its hardness. The property of Ductility of a metal allows us to make a wider use of them. Some most ductile metals are gold, silver, copper etc. whereas some of the metals with very less ductility are tungsten, steel and other alloys as they are very hard to transform into a thin wire.
A metal with less ductility can be malleable as it can have the ability to be converted into a thin sheet. Not all the metals are ductile but some of them have high ductility, some have less and some of them are non ductile.
Answer:
Let's look at another example: 3/4 is the same as 6/8. How do you know this to be true? The proof is in the pie chart diagram. The top circle has 3 out of the 4 parts shaded in. The bottom circle has 6 of the 8 parts shaded in. However, both fractions refer to the same part of the circle.
You can check your results by dividing. Here, both the numerator (6) and the denominator (8) are divisible by 2.
Finding 2nd Fraction Numerators
What would happen if a numerator were missing? Well, if you're given two fractions and told that they are equivalent fractions, you can find the missing numerator using multiplication or division.
In all equivalent fractions, both the numerator and denominator of the first fraction can be multiplied by the same number to get the numerator and denominator of the second fraction.
Say one of the numerators was missing from those pie chart equations:
3 / 4 = x / 8
You can see that there is an x alongside one of the numerators. That represents the number you are trying to find.
The answer lies in discovering what the first denominator can be multiplied by to get the other denominator. You might be good enough at your times tables to know that 4 times 2 is 8. But you can also check this number by dividing the denominator (8) by the denominator (4), which equals 2.
