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Crank
3 years ago
6

Convert 5 pounds to kilograms Help me pleaseeee

Chemistry
2 answers:
s2008m [1.1K]3 years ago
6 0

Answer:

2.268

Explanation:

5 lb × 0.45359237 = 2.26796185 kg

How to convert Pounds to Kilograms

1 pound (lb) is equal to 0.45359237 kilograms (kg).

1 lb = 0.45359237 kg

The mass m in kilograms (kg) is equal to the mass m in pounds (lb) times 0.45359237:

m(kg) = m(lb) × 0.45359237

Example

Convert 5 lb to kilograms:

m(kg) = 5 lb × 0.45359237 = 2.268 kg

Hope this helped!!!

gladu [14]3 years ago
4 0

Answer:

2.26796 kg

Explanation:

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The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make
natta225 [31]

Answer:

the energy of the third excited rotational state \mathbf{E_3 = 16.041 \ meV}

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = \dfrac{m_1 \times m_2}{m_1 + m_2}

μ = \dfrac{1 \times 35}{1 + 35}

μ = \dfrac{35}{36}

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ  = \\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \  kg

μ  = 1.6139 × 10⁻²⁷ kg

r_o = 127 \ pm = 127*10^{-12} \ m

The rotational level Energy can be expressed by the equation:

E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)

where ;

J = 3 ( i.e third excited state)  &

I = \mu r^2_o

E_J= \dfrac{h^2}{8  \pi  \mu r^ 2 \mur_o } \times J ( J +1)

E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8  \times  \pi ^2  \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2  } \times 3 ( 3 +1)

E_3= 2.5665 \times 10^{-21} \ J

We know that :

1 J = \dfrac{1}{1.6 \times 10^{-19}}eV

E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV

E_3 = 16.041  \times 10 ^{-3} \ eV

\mathbf{E_3 = 16.041 \ meV}

8 0
3 years ago
What is the speed of light of an orange light with a wavelength of 600nm and a frequency of 5.00x1014?
vovangra [49]

Answer:

3 × 10^8 m/s

Explanation:

The wavelength, can be calculated by using the following formula;

λ = v/f

Where;

λ = wavelength (m)

v = velocity/speed of light (m/s)

f = frequency (Hz)

According to the provided information in this question, λ = 600nm i.e. 600 × 10^-9m, f = 5.00 x 10^14 Hz

Hence, using λ = v/f

v = λ × f

v = 600 × 10^-9 × 5.00 x 10^14

v = 6 × 10^-7 × 5.00 x 10^14

v = 30 × 10^(-7 + 14)

v = 30 × 10^ (7)

v = 3 × 10^8 m/s

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3 years ago
In which set do all elements tend to form anions in binary ionic compounds? li, na, k n, o, i c, s, pb k, fe, br?
pav-90 [236]

Atoms or molecule after gaining of electron possesses negative charge and is known as anion.

For the given sets:

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The given elements are alkali metals and have tendency to lose electrons easily and form cations.

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The given elements are non-metals and are electronegative. So, they gain electrons easily and form anion.

  • C, S, Pb

Carbon has tendency to form bond by sharing of electrons, Sulfur has tendency to gain electrons and form anion whereas Lead has tendency to lose electron.

  • K, Fe, Br

Potassium and Iron has tendency to lose electron and form cation whereas Bromine has tendency to gain electron to form anion.

Hence, from the given sets, all elements of set: N, O, I have tendency to form anions in binary ionic compounds.

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In-s [12.5K]

Answer:

C

Explanation:

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