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Murrr4er [49]
3 years ago
5

What is the solution to this problem w-2=-3

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0
W - 2 = -3

w = -3 + 2      added 2 to both sides

w = -1

hope this helps, God bless!
USPshnik [31]3 years ago
4 0
The given equation is w - 2 = -3. We can add 2 to both sides to get w = -1. Therefore, the answer to your query is w = -1. Hope this helps and happy Halloween!
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NEED Help!<br> 111=14g<br> and also 13.65=h + 4.88
crimeas [40]

Answer:

In this question if g and h is constant then;

111 = 14g

14g = 111

g = 111/14

g = 27.7 ~ 28

And also,

13.65 = h + 4.88

h + 4.88 = 13.65

h = 13.65 - 4.88

h = 8.77

Hope it helps!

3 0
2 years ago
If the silver accounts for 84% of the bar's weight, what is the weight of the silver?
lidiya [134]
Weight=8.15 ounces
silver=84%of the total weight
silver=(84/100)×8.15 ounces
silver= 0.84×8.15 ounces
silver=7.5795 ounces
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8 0
2 years ago
6.<br> 5x – 2y = 17<br> 2x + 3y = 3<br><br> How do i do elimination on this problem.
kolbaska11 [484]

Answer:

Add the equations in order to solve the first variable. Plug this value into the other equation in order to solve the remaining variables.

The point form is (3,-1)

The equation form is x = 3, y = -1

Hope this helps!

<u><em>PLEASE, </em></u>consideer brainliest. I only have 3 left and then my rank will go up.

3 0
3 years ago
A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with
Ratling [72]

Answer:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(10.5,0.3)  

Where \mu=10.5 and \sigma=0.3

We are interested on this probability

P(X>10.983)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

8 0
3 years ago
Pls help help me out help help pls help quick
kotegsom [21]
The answer is b I hope this help
7 0
3 years ago
Read 2 more answers
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