Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer: 0.15%
Step-by-step explanation: edmentum
it's easy to by them Cheaper tbh with you
and it's a quiz Right??
Answer:
x = 4
Step-by-step explanation:
3x - 1 = 11
3x = 1 + 11
3x = 12
x = 12/3
x = 4
Thus, The value of x is 4
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<em>2400 is increased by 30%.</em>
so,
2400 + (30/100 * 2400)
2400 + (30 * 24)
2400 + 720
3120
<em>this number is decreased by 20%.</em>
so,
3120 - (20/100 * 3120)
3120 - (2 * 312)
3120 - 624
2496
therefore, the final number will be 2496.
