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Step2247 [10]
2 years ago
14

Describe a simple experiment that can be perfomed in tha laboratory to demonstrate the formation of iron3chloride from iron fill

ings
Chemistry
1 answer:
dsp732 years ago
6 0

Answer:

laboratory use the organic substances dissolve in water methanol or ethanol then Sinha to rise iron chloride solution is added a transient permanent coloration usually purple green or blue indicate the presence of a funnel or an hall

Explanation:

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HOW MANY M ARE IN 3.0X105 MM?
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The answer to the question is 300meters.

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3 years ago
Atomic size of inert gases do not affect you inertness why​
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Because your body has built-in resistance to certain gases, no matter the size of the gas cloud.

That is why we are able to stay non-inert to these types of gases, like Carbon dioxide.

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2 years ago
If the human body were a car, glucose would be:
NeTakaya
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8 0
3 years ago
When a person pushes off a wall with 15N of force,how much force does the wall push back
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5 0
3 years ago
You need to prepare 1 L of the citric acid/citrate buffer. You have chosen to use Method 1 (see lab presentation). Calculate the
prisoha [69]

Answer:

3.11 is the pH of the buffer

Explanation:

The pH of a buffer is obtained using H-H equation:

pH = pKa + log [Conjugate base] / [Weak acid]

<em>Where pH is the pH of the buffer, pKa = -log Ka = 3.14 for the citric buffer and [] could be taken as the moles of each species.</em>

The citric acid,HX (Weak acid), reacts with NaOH to produce sodium citrate, NaX (weak base) and water:

HX + NaOH → H2O + NaX

That means the moles of NaOH added = Moles of sodium citrate produced

And the resulitng moles of HX = Initial moles - Moles NaOH added

<em>Moles HX and NaX:</em>

Moles NaOH = 0.100L * (0.65mol / L) = 0.065 moles NaOH = Moles NaX

Moles HX = 0.300L * (0.45mol / L) = 0.135 moles HX - 0.065 moles NaOH = 0.070 moles HX

Replacing in H-H equation:

pH = 3.14 + log [0.065mol] / [0.070mol]

pH = 3.11 is the pH of the buffer

8 0
3 years ago
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