Answer:
Fine,I guess :)...btw haii
80=6th graders
40=5th graders
80+40=120
120/22= 60/11
120/25=24/5
120/30= 4
There are 30 students in each class because he teaches 4 class and 120/30 will give you 4.
Answer:
d 3
Step-by-step explanation:
d3
hello,
Jack wants to know how many families in his small neighborhood of 60 homes would help organize a neighborhood fund-raising party. He put all the addresses in a bag and drew a random sample of 30 addresses. He then asked those families if they would help organize the fund-raising party. He found that 12% of the families would help organize the party. He claims that 12% of the neighborhood families would be expected to help organize the party. Is this a valid inference?
Yes, this is a valid inference because the 30 families speak for the whole neighborhood
it's the correct one because if he ask 30 families so they talk to their neighborhood so its will be 60 ;) so its correct,
hope this help
Answer:
C = $5 + $1.5(w)
Step-by-step explanation:
Given the following information :
Total shipping cost :
One time fee + fee based on package weight
Given the table :
Weight in pounds - - - - Total shipping cost($)
___4__________________11
___8__________________17
___12_________________23
___16_________________29
We can deduce from the table
For a package that weighs (w) 4 pounds
Total shipping cost = $11
Let one time fee = f
Fee based on weight = r
f + 4(r) = 11 - - - - - (1)
For a package that weighs (w) 8 pounds
Total shipping cost = $17
One time fee = f
Fee based on weight = r
f + 8r = 17 - - - - - (2)
From (1)
f = 11 - 4r - - - (3)
Substitute f = 11 - 4r in (2)
11 - 4r + 8r = 17
-4r + 8r = 17 - 11
4r = 6
r = 6/4
r = 1.5
Put r = 1.5 in (3)
f = 11 - 4(1.5)
f = 11 - 6
f = 5
Hence one time fee = $5
Charge based on weight = $1.5
Hence, Total shipping cost 'C' for a package weighing 'w' will be :
C = $5 + $1.5(w)
