(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
Answer:
Directly proportional relationships always pass through the origin (0,0). There are other linear relationships that do not pass through the origin.
Answer:
1 + root 5, 1 - root 5
Step-by-step explanation:
I assume you mean 3x^2-6x-12=0.
First, note that you can divide both sides by 3. You get:
x^2-2x-4=0
Use the quadratic equation.

Therefore, x=1 + root 5, 1 - root 5
Step1: group the first two terms together
next step 2:factor out a GFC from each separate binomical
next step 3: factor out the common binomial
The area of this trapezoid is 90 square feet.
<h3>Explanation : </h3>
Before we know the answer, let's we know the formula first. The formula for count the area of trapezoid is :

If :
- A = area of trapezoid
- a = bottom bases of trapezoid
- b = top bases of trapezoid
- h = height of trapezoid
Okay, let's we count its :
We know that :
- a = bottom bases of trapezoid = 18 feet
- b = top bases of trapezoid = 12 feet
- h = height of trapezoid = 6 feet
Question : A = area = ... ?
Answer :

<u>Subject</u><u> </u><u>:</u><u> </u><u>Mathematics</u>
<u>Keyword</u><u> </u><u>:</u><u> </u><u>Count</u><u> </u><u>The</u><u> </u><u>Area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>shape</u>