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Vilka [71]
3 years ago
13

How do the scientists Mendeleev and Moseley differ on their arrangement for the periodic table? A) Their periodic table was arra

nged the same. B) Moseley arranged the elements based on atomic masses while Mendeleev arranged the elements based on atomic number. C) Moseley arranged the elements based on atomic numbers while Mendeleev arranged the elements based on atomic masses. D) Moseley arranged the elements based on the number of protons while Mendeleev arranged the elements based on x-ray frequency.
Chemistry
2 answers:
makkiz [27]3 years ago
6 0

Explanation:  He made the atomic number instead of atomic mass. This fixed the discrepancies with elements such as tellurium and iodine.

julia-pushkina [17]3 years ago
5 0

Answer:

C) Moseley arranged the elements based on atomic numbers while Mendeleev arranged the elements based on atomic masses.

Explanation:

I did it on USA test prep

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Answer: 0.5 mole Mg

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The ideal gas heat capacity of nitrogen varies with temperature. It is given by:
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Answer:

A)  1059 J/mol

B)  17,920 J/mol

Explanation:

Given that:

Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4

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C_p=C_v+R

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C_V = 21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4

A).

The formula for calculating change in internal energy is given as:

dU=C_vdT

If we integrate above data into the equation; it implies that:

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4\,) du

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 1059J/mol

Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.

B).

If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.

then T = 273 K & T2 = 1073 K

∴

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})273/1+(5.82*10^{-7})1073/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 17,920 J/mol

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