Answer:
0.529
Explanation:
Let's consider the reaction A → Products
Since the units of the rate constant are s⁻1, this is a first-order reaction with respect to A.
We can find the concentration of A at a certain time t () using the following expression.
where,
[A]₀: initial concentration of A
k: rate constant
Answer:
86
Explanation:
The reaction that takes place is:
- C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
First we <u>convert moles of ethanol to moles of water</u>:
- 1.6 mol ethanol * = 4.8 mol H₂O
Then we <u>convert moles of water to grams of water</u>, using its molar mass:
- 4.8 mol H₂O * 18 g/mol = 86.4 g
So 84.6 grams of water will be produced.
Answer: <u><em>Shape and position</em></u>
Explanation:
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Answer:
2192.64 PSI.
Explanation:
- From the general law of ideal gases:
<em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the container in L (V = 1650 L).
n is the no. of moles of the gas in mol (n = 9750 mol).
R is the general gas constant (R = 0.082 L.atm/mol.K).
T is the temperature of the gas in (T = 35°C + 273 = 308 K).
∴ P = nRT/V = (9750 mol)(0.082 L.atm/mol.K)(308 K)/(1650 L) = 149.2 atm.
- <u><em>To convert from atm to PSI:</em></u>
1 atm = 14.696 PSI.
<em>∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.</em>
Answer:
Equilibrium concentrations of the gases are
Explanation:
We are given that for the equilibrium
Temperature,
Initial concentration of
We have to find the equilibrium concentration of gases.
After certain time
2x number of moles of reactant reduced and form product
Concentration of
At equilibrium
Equilibrium constant
Substitute the values
By solving we get
Now, equilibrium concentration of gases