We can start by solving for 10-5a+(18-b). By plugging in a and b, we get
10 - 10 + (18 - 11)= 7
28 ÷ (a × 2) = 28/4 = 7
20 + b − (4 × a) = 31 - 8 = 23
49 − 43 + (a ÷ a) = 49 - 43 + 1 = 7
30 − 25 + (b − 9) = 5 + 2 = 7
50 ÷ a − (b + 20) = 25 - 31 = -6
So, 28 ÷ (a × 2), 49 − 43 + (a ÷ a), and 30 − 25 + (b − 9) will all have the same answer as 10−5a+(18−b)
Answer:
75%
Step-by-step explanation:
You pick a card at random. 6 7 8 9 What is P(not 9)? Write your answer as a percentage. %
Given the following
Total cards = 4 (6,7,8,9)
If the card is not 9, the required card will be (6,7,8)
Number of cards that are not 9 is 3
Probability = expected/total
Pr(not 9) = 3/4
express as percent
Pr(not 9) = 3/4×100
Pr(not 9) = 75%
Answer:
Here's a two step equation for example: 4.8y - 6.9 = 3.18
Step-by-step explanation:
How I solve it is using: Sadmep.
wth is that?
Well, it's pemdas backwards. You use this version for solving 2 step equations. But pemdas, not a two step equation.
But, how to solve it: Sadmep..S stands for subtraction...do I see it? Yes! So we are going to do inverse operations..what's the inverse of subtraction..Addition! So you are going to put an addition sign right under the subtraction, and put 6.9..now what you do to one side, you have to do to the other. So add 6.9 to 3.18. Now once you did that, you have to add, but you can't add the 6.9 and the 6.9, you have to cross it out, but you HAVE to hadd 3.18 and 6.9..so do that. So for right now your answer should be: 4.8y = 10.08...let's finish solving! Now since there are two unlike terms, when it comes down to literally this, you have to divide each side by the number with the variable. So: 4.8y divided by 4.8...and 10.08 divided by 4.8.. now remember what I said..4.8y divided by 4.8 are alike so you have to cross it out. But you HAVE to divide 10.08 by 4.8. And once you do that..:::: y = 2.1 ....see? easy and simple!
The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size. That is,
The mean of a particular sample is equal to the mean of the set the sample was taken from. That is,
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