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Korvikt [17]
2 years ago
8

How do you simplify 11 to the power of 6

Mathematics
1 answer:
Misha Larkins [42]2 years ago
8 0

Answer:

1771561

Step-by-step explanation:

You are referring to

11 {}^{6}

a formula called Power of Power

(11 {}^{2} ) {}^{3}  = 121 \times 121 \times 121 = 1771561

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12 &lt; k + 11<br><br><br> The solution of the inequality is <br><br> (pls answer fast)
Free_Kalibri [48]

Answer:

Solve for K by simplifying both sides of the inequality, then isolating the variable.

Inequality Form:

k > 1

<u>Interval Notation</u>:

(1, ∞)

Step-by-step explanation:

4 0
3 years ago
What is the square root of 9/16, 9 to the power of two
lbvjy [14]

Answer:

\frac{3}{4} , 9

Step-by-step explanation:

\sqrt{9/16} = \sqrt{9} ÷ \sqrt{16} = \frac{3}{4}

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3 years ago
Unit 2 Functions Classwork - Homework Day 5 Piecewise Functions
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6 0
3 years ago
The average age of staff in the maths department is 40.
pashok25 [27]

Answer:

Cerian is 28 years old

Step-by-step explanation:

The given parameters are;

The average age of the staffs in the mathematics department = 40

The number of staffs in the department = 7

The average age of Jill, Nicky and Wendy = 41

The average age of Andy, Alan and Cathy = 43

From the given parameters, we have;

The average age of the staffs in the mathematics department = (The sum total of the ages of the members of the math department)/(The number of staffs in the department)

Therefore;

40 = (The sum total of the ages of the members of the math department)/ (7)

From which we have;

The sum total of the ages of the members of the math department = 40 × 7 = 280

Which gives;

Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age = 280 years

The average age of Jill, Nicky and Wendy = 41

Given that Jill, Nicky, and Wendy make up 3 of the 7 members of staffs, we have;

The average age of Jill, Nicky and Wendy = (The sum total of the ages of Jill, Nicky, and Wendy)/(The number of staff Jill, Nicky, and Wendt make)

Therefore;

The sum total of the ages of Jill, Nicky, and Wendy = 41 × 3 = 123

Which gives;

Jill's age + Nicky's age + Wendy's age = 123 years

Similarly, the sum total of the ages of Andy, Alan, and Cathy = 43 × 3 = 129

Which gives;

Andy's age + Alan's age + Cathy's age = 129 years

Therefore;

Cerian's age = (Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age) - (Jill's age + Nicky's age + Wendy's age) + (Andy's age + Alan's age + Cathy's age)

∴ Cerian's age = 280 years - 123 years - 129 years = 28 years

6 0
3 years ago
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