Answer is: chemical.
If the arrangement of particles is changed, that is chemical change or chemical reaction (new substance is formed).
In physical change, the bonds between oxygen and hydrogen can not be separated.
For example, balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s).
Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.
Answer:
<u>the reaction will shift to the left </u>and produce more reactants
Explanation:
Step 1: data given
Kc = 190
Temperature = 1000 K
[CO] = 0.025 M
[H2] = 0.045 M
[H2O] = 0.025 M
[CH4] = 0.046 M
When Q=Kc, the system is at equilibrium and there is no shift to either the left or the right.
When Q<Kc, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.
When Q>Kc, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants
Step 2: The balanced equation
CO(g) + 3 H2(g) ⇌ H2O(g) + CH4(g)
Step 3: calculate Q
Q = [H2O][CH4] / [CO][H2]³
Q = (0.025*0.046) / (0.025*0.045³)
Q = 504.8
Q > Kc
This means there are more products than reactants. To decrease the amount of products, <u>the reaction will shift to the left </u>and produce more reactants
Answer: Theres no question here
Explanation:
The partial pressure of oxygen, P(O₂) is 198.83 mmHg.
<h3>What is partial pressure of a gas?</h3>
The partial pressure of a gas is the pressure gas will exert in a mixture of gases which do not react chemically together.
The sum of partial pressure of gases at atmospheric pressure = 760 mmHg
P(N₂) + P(H₂O) + P(CO₂) + P(O₂) + P(other) = 760 mmHg
P(N₂) = 0.72 atm = 547.2 mmHg
P(H₂O) = 7.7 torr = 7.7 mmHg
P(CO₂) = 0.37 mmHg
P(other) = 0.97 kPa = 5.9 mmHg
P(O₂) = 760 - (547.2 + 7.7 + 0.37 + 5.9) = 198.83 mmHg
Therefore, the partial pressure of oxygen, P(O₂) is 198.83 mmHg.
Learn more partial pressure at: brainly.com/question/14119417
#SPJ1
Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
![Rate = k[AB]^2](https://tex.z-dn.net/?f=Rate%20%3D%20k%5BAB%5D%5E2)
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
Where,
is the initial concentration = 1.50 mol/L
is the final concentration = 1/3 of initial concentration =
= 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-


<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>