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vesna_86 [32]
3 years ago
13

Qualitative measurements involve numerical measurements while quantitative measurements record descriptions.

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
6 0
This is false quantitative is numerical while qualitative is descriptive
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Honeybee venom is a solution that contains formic acid, which gives the venom an approximate ph of 5.0. which substance is more
Genrish500 [490]
Those substances which has pH less than 5 are more acidic than Honeybee Venom. Some of them are listed below along with their pH scale,

                  1) <span>Acid rain and Tomato Juice has a pH of 4.

                  2) Soda and Orange Juice has a pH of 3.

                  3) Vinegar and Lemon Juice has pH of 2.

                  4) Gastric acid has a pH of 1.

                  5) Battery Acids have pH of zero.</span>
5 0
3 years ago
A sample of nitrogen gas has the temperature drop from 250.°c to 150.°c at constant pressure. what is the final volume if the in
Leviafan [203]
Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where   V- volume , T - temperature and k - constant 
\frac{V1}{T1} =  \frac{V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,

\frac{310 mL}{523 K} =  \frac{V}{423K}
V = 251 mL
the new volume is 251 mL 
6 0
3 years ago
Find the % by mass of the solute in 129.54 g C6H1206 in 525 g H20.
belka [17]

Answer:

19.79%

Explanation:

mass % = (mass solute / total mass) * 100

total mass = 129.54 + 525 = 654.54

solute = C6H12O6

(129.54/654.54) = .1979

.1979 * 100 = 19.79%

7 0
3 years ago
Lab: Calorimetry and Specific Heat
gayaneshka [121]

Answer:

Title for the lab--->Calorimetry and Specific Heat

Name:

Teacher:

Date:

Purpose: Explore how the specific heat of a substance can be determined using a “coffee cup” calorimeter.

Question: How can you determine the specific heat of a metal using a calorimeter?

Hypothesis: If a metal has a low specific heat, then the metal could make an excellent material for cookware because it takes less heat to raise the temperature of the metal to cook food.

MATERIALS:

- Two polystyrene coffee cups

- Lid for polystyrene cup

- Thermometer      

- 250 mL beaker        

- 400 mL beaker    

- Ring stand    

- Two buret clamps    

- Hot plate  

- Test-tube holder    

- 50 mL graduated cylinder  

- Water    

- aluminum, copper, iron, and lead powder    

- Analytical balance

PROCEDURE:

1) Set up a 600 mL beaker and add 400 mL of dis"lled water inside and place it on a hot plate un"l it boils. Also set up 2 dry Styrofoam cups with a lid aside and add 100.0 mL tap water (calorimeter water) inside.

2) In the boiling water, place the unknown metal sample inside for about 30 min. Before though, weigh it accurately and record the mass on your data sheet.

3) After 30 min, take the temperature of boiling water to the nearest 0.1 °C (Ini"al temp of metal), then take the metal out of the boiling water and replace it into Styrofoam cups filled with room temperature tap water. Ini"al temperature of water is the room temperature of the tap water.

4) Take every 15 seconds for about 2 minutes the temperature of water inside the calorimeter with a thermometer inserted through the hole in the lid. Gently swirl the cup to mix the contents and record the temperature. Use the highest temperature.

5) Calculate the specific heat of the metal sample.

then the table will be in the picture i posted on here  

next is your ---> Analysis /Conclusion

Analysis:

Analyzed from the data above, we know the temperature that is measured depends on the amount of mole in the solution. If the amount of mole in the solution is large, the temperature will be as well. After a few moments, the temperature rises and falls, and in some instances, it remains steady.

Conclusion:

In conclusion, I do believe my hypothesis was supported through my experiments. Through said experiments, I identified the unknown metal as we calculated the changes in the heat, and found that the metals that should be put to use are copper and iron metals. Copper and iron have a low specific heat, which makes these ideal metals when creating cookware. When a metal has low specific heat, it needs less energy to produce heat and it cools down with less energy as well. For these reasons, my hypothesis is supported.

Explanation:

hope this helps :)

5 0
2 years ago
During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2
ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass  of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol =<u> 12.81 grams</u>

Step 6:  Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = <u>75.70 grams CO2</u>

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = <u>34.29 grams</u>

3 0
3 years ago
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