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omeli [17]
3 years ago
15

Line AE and line DF are parallel. If m∠ABG = 12x and m∠HCF = 11x + 9, what is m∠HCF?

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0

Answer:

108 degrees

Step-by-step explanation:

vladimir2022 [97]3 years ago
3 0

Answer:

C. 108°

Step-by-step explanation:

  • ∠ABG and ∠HCF are alternate exterior angles which mean they are congruent (equal in measure)
  • So, if 12x = 11x+9, use railroad tracks to solve

12x = 11x + 9 \\-11x    -11x\\---------------------\\x = 9

  • Now substitute 9 in for x in the equation for ∠HCF

11x+9 = ∠HCF

11(9) + 9 = ∠HCF

99 + 9 = ∠HCF

108 = ∠HCF

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After the drama club sold 100 tickets to a show, it had $300 in profit. After the next show, it had sold a total of 200 tickets
ZanzabumX [31]

Answer:

B. y-300=4(x-100)

Step-by-step explanation:

4 0
3 years ago
(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
Tyee went shopping for a new video game because of a sale. The store was offering a 45% discount. If the price on the tag was p,
monitta

Answer:

It would be 0.45p.

Step-by-step explanation:

6 0
3 years ago
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What is the scale factor?
Fed [463]

Answer:

2

Step-by-step explanation:

it literally doubles in size

5 0
2 years ago
Read 2 more answers
Please help and show work​
melisa1 [442]

Answer:

first one is simnple cross multiply and divide

12*7=4x

84=4x

x=21

2nd same process but more steps

7x=5(x+8)

7x=5x+40

7x-5x=40

2x=40

x=20

Step-by-step explanation:

4 0
3 years ago
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