Answer:
1. 4y-12
2. c
For #1 you distribute the 4 to the y and the 3. 4 times 3 equals 12.
For #2 you factor out the 3 and you get 3(5x+1)
we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Answer:
3.6
Step-by-step explanation:
Answer:
9625
Step-by-step explanation:
If 385 alcohol swabs were defective, then 385 is 4% of all produced alcohol swabs.
385*25 = 9625
9625 alcohol swabs were produced