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enot [183]
3 years ago
7

Answer for both and explain B 20+ points

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

<u>Given function:</u>

  • g(x) = x² - 6x + c

a)

  • c = 2

<u>Th x-intercept found when g(x) = 0</u>

  • x² - 6x + 2 = 0

<u>Solve the equation to find the values of x:</u>

  • x² - 6x + 2 = 0
  • x² - 6x + 9 = 7
  • (x - 3)² = 7
  • x - 3 = ±√7
  • x = 3 ± √7

The x-intercepts are (3 + √7, 0) and (3 - √7, 0)

b)

  • c = 10

<u>Solve as above:</u>

  • x² - 6x + 10 = 0
  • x² - 6x + 9 + 1 = 0
  • (x - 3)² = -1

The left side is a square of a number which is always positive, the right side is negative.

It means there is no solution, so no-x-intercepts.

The graph of the function lies above the x-axis.

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To find the product of (−2√20k)(5√8k3), first write using a single radical. Which expression is equivalent to the given product?
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Answer:

Assuming the variable is included under the radical,

-40k²√(10)

Step-by-step explanation:

(-2\sqrt{20k})(5\sqrt{8k^3})

First we will simplify the first factor,

-2\sqrt{20k}

We will write 20 as a product of factors:

-2\sqrt{4*5k}

We know the square root of 2 is 2, so we pull a 2 out:

-2(2)\sqrt{5k}\\\\=-4\sqrt{5k}

Now we will simplify the second factor,

5\sqrt{8k^3}

We will rewrite 8 as a product of factors, as well as the variable:

5\sqrt{2*4*k^2*k}

The square root of 2 is 2, so we pull a 2 out.  Additionally, the square root of k² is k, so we pull that out:

5(2)(k)\sqrt{2k}\\\\=10k\sqrt{2k}

This gives us the product

(-4\sqrt{5k})(10k\sqrt{2k})

Multiplying the coefficients, we have

-4(10k)(\sqrt{5k})(\sqrt{2k})\\\\=-40k(\sqrt{5k})(\sqrt{2k})

Multiplying the two radicals, we have

-40k\sqrt{5k*2k}\\\\-40k\sqrt{10k^2}

The square root of k² is k, so we pull a k out, leaving

-40k(k)\sqrt{10}\\\\=-40k^2\sqrt{10}

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4 years ago
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