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enot [183]
3 years ago
7

Answer for both and explain B 20+ points

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

<u>Given function:</u>

  • g(x) = x² - 6x + c

a)

  • c = 2

<u>Th x-intercept found when g(x) = 0</u>

  • x² - 6x + 2 = 0

<u>Solve the equation to find the values of x:</u>

  • x² - 6x + 2 = 0
  • x² - 6x + 9 = 7
  • (x - 3)² = 7
  • x - 3 = ±√7
  • x = 3 ± √7

The x-intercepts are (3 + √7, 0) and (3 - √7, 0)

b)

  • c = 10

<u>Solve as above:</u>

  • x² - 6x + 10 = 0
  • x² - 6x + 9 + 1 = 0
  • (x - 3)² = -1

The left side is a square of a number which is always positive, the right side is negative.

It means there is no solution, so no-x-intercepts.

The graph of the function lies above the x-axis.

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=> A [4^2] = - C

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That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4

2) Now you verify the images for that function for all the x-values of the table:

x = 2 => f(2) + [1/4] 4 ^ (2 - 1) - 4 = [1/4] 4 - 4 = 4 / 4 - 4 = 1 - 4 = - 3 => check

x = 3 => f(3) = [1/4] 4^ (3 - 1) - 4 = [1/4] 4^2 - 4 = 16 / 4 - 4 = 4 - 4 = 0 => check

x = 4 -> f(4) = [1/4] 4^ (4-1) - 4 = [1/4] 4^(3) - 4 = (4^3) / 4 - 4 = 4^2 - 4 = 16 - 4 = 12 => check.

Therefore, you have proved that the answer is the fourth option.
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