<h3>
Answer: Choice A, x^12y^3</h3>
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Explanation:
Think of x^4y as x^4y^1. When we raise this to the third power, we multiply the outer exponent 3 by each inner exponent
x^4 turns into x^12
y^1 turns into y^3
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This is one way to show your work
(x^4y)^3
(x^4y^1)^3
x^(4*3)*y^(1*3) ... multiplying outer exponent by each inner exponent
x^12y^3
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A more lengthy way to get the answer is to write x^4y out three times multiplying by itself that many times. The outer exponent 3 tells us we will have three copies of x^4y multiplied with itself.
(x^4y)^3 = (x^4y)*(x^4y)*(x^4y)
(x^4y)^3 = (x^4*x^4*x^4)*(y*y*y)
(x^4y)^3 = ( x^(4+4+4) ) * ( y^(1+1+1) )
(x^4y)^3 = x^12y^3
There is a really easy way to find this out I can't really help you so if you just look it up on google you should get your awnser
Answer:
2(8a + 8)
Step-by-step explanation:
The easiest way to do this is to substitute <em>a</em> for a number. For example, let's just make things easy and make <em>a </em> = 1.
So, if a = 1, the expression 16a + 8 would be 16(1) + 8 = 24.
Let's find all the expressions that would also equal 24 if <em>a = </em>24.
Plug in 1 for <em>a</em> in each of the equations. You will find that 2(8a + 8) will not equal 24 if <em>a </em>equals 1.
2(8a + 8)
2(8(1) + 8
2(8 + 8)
2(16)
32
Answer:
(a) = iv
b = i
c= ii
d = iii
Q-3
- radical 3
Step-by-step explanation:
Step-by-step explanation:
the answer to your question with roster method is
(-5,-4,-3,-2 and -1)
