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Fed [463]
3 years ago
15

How are mass and free fall related to acceleration?

Physics
2 answers:
OleMash [197]3 years ago
7 0

Answer:

All objects free fall at the same rate of acceleration regardless of their mass. But, if you were to increase the force on the object then the acceleration will increase while the mass decreases. Therefore, the greater force on more massive objects is offset by greater mass.

Dmitrij [34]3 years ago
4 0

Explanation:

The acceleration of the object equals the gravitational acceleration. The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration hope that helps

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The only pictures we have of the Milky Way are from ____________________.
erastova [34]
Most pictures used as the milky way are actually just pictures of other galaxies (such as Andromeda) that we just figure are similar enough to ours. 

<span>We can take a side ways photo of our own galaxy, but not a front view. </span>
3 0
3 years ago
A book with a mass of 1.2 kg sits on a bookshelf. If it has gravitational potential energy of 50 j, how high is the shelf ? The
Tatiana [17]

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B

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Thanks+BRAINLIST
Fynjy0 [20]

Answer:

it change speed

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3 years ago
As current increases in an electromagnet’s coil, the strength of the magnet field _______(increases, decreases, remains the same
Ahat [919]

Answer:

increases

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7 0
3 years ago
A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the
Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

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W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

7 0
3 years ago
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