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TEA [102]
3 years ago
14

As current increases in an electromagnet’s coil, the strength of the magnet field _______(increases, decreases, remains the same

)
Physics
1 answer:
Ahat [919]3 years ago
7 0

Answer:

increases

Explanation:

because as when the electimagnatics coul coul starts to increase the magnetic field also increases

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The answer is going to be C.

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What two elements are named after Dimitri Mendeleev?
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Carbon dioxide is a substance made up of atoms of carbon and oxygen in fixed ratios. Carbon dioxide is?
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We wish to obtain a equal sized inverted image of a candel flame on a screen kept at a distance of 4m from the candle flame a) n
soldier1979 [14.2K]

A) To obtain an inverted image of an object of same size a convex lens is used.

B)

In this question we have given

Distance between candle flame and screen=4

it means distance between candle flame and lens +distance between lens and screen =4m

u+v= 4m

u= v

therefore, 2u= 4m

or, u=-2m              ( u is taken negative because it lies on left side of the lens)

and v=2m

we have to find the focal length of convex lens

\frac{1}{f}  =  \frac{1}{v}   -  \frac{1}{u}\frac{1}{f}  =  \frac{1}{2} - ( -  \frac{1}{2} ) \\  \frac{1}{f}  = \frac{1}{1}\\ f = 1m

Hence, Focal length of the lens is 1m

and lens should be placed at a distance of 2m from the flame

4 0
3 years ago
You are presented with several wires made of the same conducting material. The radius and drift speed are given for each wire in
jekas [21]

\begin{array}{ccc}&\text{Radius} & \text{Drift Speed}\\d) & 2 \; r &2.5 \; v\\a) & 3 \; r &1 \; v\\b) & 4 \; r &0.5 \; v\\c) & 1 \; r &5 \; v\\\end{array}

<h3>Explanation</h3>

I = v \cdot A \cdot n \cdot q,

where

  • I is the current;
  • v is the drift speed;
  • A is the cross-section area of the wire,
  • n is the number of charge carrier per unit volume, and
  • q is the charge on each charge carrier.

Area of a circular cross-section:

A = \pi \cdot r^{2},

where

  • r is the radius of the wire.

n and q are the same for all four samples, for they are made out of the same material.

As a result, I of each wire is directly proportional to v \cdot r^{2} where the value of \pi \cdot n \cdot q is constant.

For each of the four wires:

\begin{array}{ccc|c}\\& r & v &I \propto v\cdot r^{2}\\a) & 3 & 1 & 9\\b) & 4 & 0.5 & 8\\c) & 1 & 5 & 5\\d) & 2 & 2.5 & 10\\\end{array}.

How do the four wires rank by their current?

d > a > b > c.

3 0
4 years ago
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