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3 years ago

The only pictures we have of the Milky Way are from ____________________.

1 answer:

3 0

Most pictures used as the milky way are actually just pictures of other galaxies (such as Andromeda) that we just figure are similar enough to ours.

<span>We can take a side ways photo of our own galaxy, but not a front view. </span>

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How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?

tatyana61 [14]

Missing part in the text of the problem:
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
$Q=m C_s \Delta T$
where
m=1.8 g is the mass of the water
$C_s = 4.18 J/(g K)$ is the specific heat capacity of the water
$\Delta T=2.5 K$ is the increase in temperature.

Substituting the data, we find
$Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E$

We know that each photon carries an energy of
$E_1 = hf$
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz$

So, the energy of a single photon of this frequency is
$E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J$

and the number of photons needed is the total energy needed divided by the energy of a single photon:
$N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons$

4 0

3 years ago

A compound is found to have a molar mass of 598 g/mol. if 0.0358 g of the compound is dissolved in enough water to make 175 ml o

zalisa [80]

π=iMRT

Where, π is Osmotic pressure,
i=1 for non-electrolytes,
M is molar concentration of dissolved species (units of mol/L)
R is the ideal gas constant = 0.08206 L atm mol⁻¹K⁻¹,
T is the temperature in Kelvin(K),

Here, to calculate M convert into standard units mg tog, ml to L, c to Kelvin
M= ( $\frac{35.8}{598}$ *10⁻³ )/ 0.175 =(5.987 *10⁻⁵)mol / 0.175L = 34.21*10⁻⁵ mol/L

π=iMRT=(1)*(34.21*10⁻⁵)*(0.08206)*(298.15)=837×10⁻⁵= 8.37×10⁻³ atm
=6.36 torr
(1 atm=760 torr, 1 Kelvin =273.15 °C, 1L=1000ml, 1g=1000mg)

3 0

3 years ago

A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If

telo118 [61]

Answer:

I₂ = 8 mG

Explanation:

The intensity of a beam is

I = P / A

Where P is the emitted power which is 3) 3

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

I₁ A₁ = I₂ A₂

I₂ = I₁ A₁ / A₂

The area of the beam if we assume that it is distributed either in the form of a sphere is

A₁ = 4π r²

We substitute

I₂ = I₁ (r₁ / r₂)²

I₂ = 2 (6/3)²

I₂ = 2 4

I₂ = 8 mG

3 0

3 years ago

Read 2 more answers

While eating a peanut butter and jelly sandwich, peanut butter drips on Diana’s shirt. She tries to remove the peanut butter fro

Valentin [98]

Answer:

The water and peanut butter have different chemical properties.

(Lipids are not soluble in water)

8 0

3 years ago

Read 2 more answers

How speed and position affect the energy possess by an object?

Svetllana [295]

Answer:

more speed means that an object has more energy, now if an object's place is something such as a hill, the potential energy will increase meaning an object will have more speed and acceleration. this is because you have the earth's gravity helping you out when the object goes downhill, giving it the higher potential energy

4 0

3 years ago