I am pretty sure it is <span>D. Microbiologist</span>
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
A chromosome is a long DNA molecule with part or all of the genetic material of an organism. and I can't think of the other one sorry.
Explanation:
The answer is A)<span> the desired gene is inserted into the genomes of the pork.
</span>
The techniques of genetic engineering are used to introduce hybrid genes for some desired substance or protein or trait into other organisms. Here, the desired gene is inserted into pork's genome and as a result, it has a <span>higher flesh-to-bone ratio</span><span>.</span>
<span>- B) is not the right answer because it is not necessary to change all the genes in the pork genome or it will be transformed into totally different organism.</span>
<span>- C) is not the right answer because the pork does not have plasmids.</span>
Answer:
Global climate change affects the distribution of species.
Explanation:
