Answer:
So, the force, F is the agent which provides the basic property of motion or rest to the body.While, the car is more obviously to have a mass, m and that the angle withe road or surface is also given which is normal to the road(i.e angle =90 degree). Then we say that lets say that the car is moving with the constant velocity of 20 m/sec and its kept unchanged by the car. So, we have the mass, m as 1 kg for the car and the value of the gravity we have the g=9.8 m/sec.
Now,
We have F=ma,
and a=v/t,
so we can have another equation for it as,
Now, providing the required data to, it; ∴t =2 sec,
F=(1)×(20/2),
- So, the car would be acting the force,F of about 10 N while the car is present on the lower region of the track.
Answer:
the action of measuring something.
Answer:
The separation distance between the two charges must be 82704.2925 m
Explanation:
Given:
Two negative charges that are both q = -3.8 C
Force of 19 N
Question: How far apart are the two charges, s = ?
First, you need to get the electrostatic force of this two negative charges:

Here
k = electric constant of the medium = 9x10⁹N m²/C²
Substituting values:

That's true.
In fact, the resistance of a wire is given by:

where

is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
We see that the resistance of the wire is inversely proportional to the cross-sectional area: A. Therefore, the narrower the wire, the smaller A, the larger the resistance. But higher resistance means that the current flowing through the wire is lower, therefore the flow of electrons in the circuit is slower, and the initial sentence is true.
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