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Sergeeva-Olga [200]
3 years ago
5

Can somebody answer this question?

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Replace x with the answer choices of x

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CDEF is a kite and m∠FCE=16 . Find m∠2<br><br> 74<br> 90<br> 16<br> 32
Rama09 [41]

Answer:

Your answer is the second option; Option B; 90.

So, m∠2 is a right triangle, due to lines CE, and FD being perpendicular. Right Triangles are always 90.

7 0
3 years ago
How do you solve Transversal problems with equations?​
Sauron [17]

Answer:

If they're equal set them equal to each other if they're supplementary you set up an equation. Where you add them up and set them equal to 180. And then you just want to solve for X.

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3 years ago
Shania and Pedro are discussing whether it is always possible to solve a right triangle, given enough information, without using
Makovka662 [10]

Answer: Shania is correct.

Step-by-step explanation:

For a right angled triangle, given two sides and an angle, we can use the sine rule or the various trigonometry identities to solve the triangle;

a/sin A = b/sinB

and

sin (angle) = opposite side/hypotenuse

cos (angle) = adjacent side/hypotenuse

tan (angle) = opposite/ adjacent

assuming a is the opposite side of angle A and b is also opposite of angle B

Otherwise, the only way to solve a triangle given two sides only is by the use of the Pythagoras theorem.

Hence, Shania is correct.

7 0
3 years ago
What is the eqation of a line passing through points (2,7) and (0,8)
ElenaW [278]

Answer:

slope intercept form is y=-1/2x+8

4 0
3 years ago
Hi everyone, I'm having trouble with this question and I'm not sure how to do it/where to start. Does anyone have a solution to
Andreyy89

This is quite an interesting problem. I am not sure how high you are in math, but I am going to use calculus I techniques to solve it. First, we need to model an equation. Let P be the total profit and x be every time you increase the cost by $10. If you think about it hard enough you come up with the equation

P(x)=(200-5x)(250+10x)

(200-5x) is the amount of plots you will be able to sell, and (250+10x) is the amount you charge for. So, at x =0

P(0)=(200-5(0))(250+10(0))=(200)(250)=$50,000

This is the initial condition where if we sell 200 plots at $250/plot.

So, this equation makes sense.

Now, let's maximize using the first derivative of the function.

Let's get it into an easily differentiable form.

P(x)=(200-5x)(250+10x)=-50x^2+2000x-1250x+50000\\=-50x^2+750x+50000

From here, differentiate the problem.

P'(x)=-100x+750

Now, set it equal to zero and solve for x.

P'(x)=-100x+750=0\\x=7.5

This a critical point of the function. Let's plug back into the original equation to see what it gives us.

P(7.5)=(200-5(7.5))(250+10(7.5))=(162.5)(325)=52,812.50

You cant sell half a plot, so we need to see what happens if we sell 162 plots and 163 plots, and then compare which one gives us more money.

In order to sell 162 plots

200-5x=162\\x=7.6Plug back into P(x) to see the profit

P(7.6)=(200-5(7.6))(250+10(7.6))=(162)(326)=52,812

Now, do the same for 163 plots

200-5x=163\\x=7.4\\P(7.4)=(200-5(7.4))(250+10(7.4))=(163)(324)=52,812

As we can see, they are the same. So, you can charge either $324 or $326 in rent. But, if your teacher is not looking for a logical answer and you can somehow sell half a plot, you can charge $325 in rent for the maximum profit.

6 0
3 years ago
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