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Sergeeva-Olga [200]
3 years ago
5

Can somebody answer this question?

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Replace x with the answer choices of x

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Ivahew [28]

the answer is 39 because you need to divide.

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djverab [1.8K]
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3 0
3 years ago
An isosceles triangle has an angle that measures 38degrees. What measures are possible for the other two angles? Choose all that
Sphinxa [80]

Answer:

  • 71° and 71°.

⠀

Step-by-step explanation:

The triangle having two sides equal along with one different side is called an isosceles triangle.

⠀

  • So, Let us assume the other sides (two equal sides) of the isosceles triangle as x. As the different side is already given in the question.

⠀

We know that,

  • The sum of all angles of a triangle is 180°

⠀

So, According to the question :

⠀

{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + x + x  =  180{}^{ \circ} }}}

⠀

{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + 2x   =  180{}^{ \circ} }}}

⠀

{\longrightarrow \it\qquad { \ {   2x   =  180{}^{ \circ} - {  38 \: }^{ \circ}}}}

⠀

{\longrightarrow \it\qquad { \ {   2x   =  142{}^{ \circ}  }}}

⠀

{\longrightarrow \it\qquad { \ {   x   =    \dfrac{142{}^{ \circ}}{2}   }}}

⠀

{\longrightarrow \it\qquad { \pmb {   x   =  71^{ \circ}  }}}

⠀

Therefore,

  • The measure of the two other angles of the isosceles triangle are 71° and 71°.
3 0
2 years ago
If y equals -12 when x equals 9 find y when x equals negative 4
alexandr1967 [171]
You can make a proportion. -12/y=9/4 -12*4-9=5.33
5 0
3 years ago
In a survey of 1,003 adults concerning complaints about restaurants, 732 complained about dirty or ill-equipped bathrooms and 38
Ganezh [65]

Answer:

a

0.716  <  p <  0.744

b

0.3498  <  p <  0.4089

c

 With the result obtained from a and b the manager can be 95 % confidence that the proportion of the population that complained about dirty or ill-equipped bathrooms are within the interval obtained at  a

and that

the proportion of the population that complained about loud or distracting diners at other tables are within the interval obtained at  b

Step-by-step explanation:

From the question we are told that

The sample size is  n  =  1003

The number that complained about dirty or ill-equipped bathrooms is e = 732

 The number that complained about loud or distracting diners at other tables is  q =  381

Given that the the confidence level is  95% then the level of significance is mathematically represented as  

         \alpha = (100- 95)\%

         \alpha = 0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table , the value is  

         Z_{\frac{\alpha }{2} } =  1.96

Considering question a

The sample proportion is mathematically represented as

           \r p  =  \frac{e}{n}

=>        \r p  =  \frac{732}{1003}

=>        \r p  =  0.73

Generally the margin of error is mathematically represented as

          E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{ \r p (1- \r p)}{n} }

          E =  1.96*  \sqrt{ \frac{ 0.73 (1- 0.73)}{1003} }

          E = 0.01402

The 95% confidence interval is  

        \r p  -  E  <  p  <  \r p +E

        0.73 - 0.01402 <  p <  0.73 +  0.01402

        0.716  <  p <  0.744

Considering question b

The sample proportion is mathematically represented as

           \r p  =  \frac{q}{n}

=>        \r p  =  \frac{381}{1003}

=>        \r p  =  0.3799

Generally the margin of error is mathematically represented as

          E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{ \r p (1- \r p)}{n} }

          E =  1.96*  \sqrt{ \frac{ 0.3799 (1- 0.3799)}{1003} }

          E = 0.0300

The 95% confidence interval is  

        \r p  -  E  <  p  <  \r p +E

        0.3798 - 0.0300 <  p <  0.3798 + 0.0300

        0.3498  <  p <  0.4089

8 0
3 years ago
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