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Thepotemich [5.8K]
4 years ago
11

What is the number in scientific notation? 0.0765 whats the answer please help

Mathematics
1 answer:
LuckyWell [14K]4 years ago
3 0
The number is 7.65 x 10^-2 in scientific notation
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Solve for x.5(x – 10) = 30 – 15x
nlexa [21]
5(x-10)=30-15x

5x-50=30-15x

20x=30+50
x=4.
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4 years ago
Three years ago, Ava lent her sister $400 to buy some clothes. Today Ava’s sister paid her loan in full with $454. What simple a
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8 0
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Read 2 more answers
ILL GIVE BRAINLIST ON WHOEVER GETS RIGHT!!!!!!!
Korvikt [17]

Answer:

hey,its option a

Step-by-step explanation:

because angle F= angle M and angle G= angle L

and angle H= angle N

To know third angle in ∆HGF

,we know sum of all angles in a triangle is 180°

______________________________

let angle H be unknown value x

x+51+36=180

x=180-87 ---------------- 1

similarly in ∆MNL

let angle be y

51+36+y=180

y=180-87----------------2

_______________________________

From 1&2 we observe qngle x= angle y

by AAA SIMILARITY THEY ARE SIMILAR

3 0
4 years ago
A bag contains 150 marbles. Some are blue, and the rest are white. There are 21 blue marbles for every 4 white marbles. How many
Soloha48 [4]

Answer:

126

Step-by-step explanation:

21 + 4 = 25  (blue plus white marbles)

150/25 = 6 (all the marbles divided by how many we know are white and blue)

21 x 6 = 126  

5 0
3 years ago
Helppppppp pleaseeeee
ratelena [41]
Let's consider each of the options; 

A) The range is the values that y can be of the function f(x). We can see that no matter what x values you put in, f(x)>0. It will never be negative. Although, if you put (1/2)^2, you can get a y value of (1/4) so this statement is incorrect. 

B) It would have to put in the x or y value into the function and check. f(0)=(1/2)^0 

You know that anything to the zero-th power gives 1, therefore, this statement is correct. 

C) Again, if you put in a value such as (1/2)^2, you would be getting a number that is smaller than 1/2, so it isn't always increasing. 

D) Again, it is possible to input any value in x and you would still be getting a positive y-value, therefore, this statement is incorrect.

Hope I helped :) 
4 0
3 years ago
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