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KatRina [158]
3 years ago
15

Two waves travel through ocean, one with wavelength 3 m, one with 6 m. Which one has greater speed?

Physics
1 answer:
spin [16.1K]3 years ago
4 0

Answer: 6m

Explanation: 6 is more than 3 and their both being measured by m

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Where did most of the comets in the Kuiper belt come from?
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The answer you would be looking for is A.

Explanation:

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3 years ago
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How does water move from the surfaces of lakes, rivers, and the ocean directly back into the atmosphere?
Sergeeva-Olga [200]

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B. Evaporation

Explanation:

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4 0
3 years ago
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. What is the dist
elena55 [62]

Answer:

Distance, d = 61.13 ft

Explanation:

It is given that,

Initial speed of the car, u = 50 mi/h = 73.34 ft/s

Finally, it stops i.e. v = 0

Deceleration of the car, a=-44\ ft/s^2

We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{0-(73.34\ ft/s)^2}{2\times -44\ ft/s^2}

s = 61.13 ft

So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.

4 0
4 years ago
A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition
Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So mg=Kx

K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m

Now we know that \omega =\sqrt{\frac{K}{m}}

So \frac{2\pi }{T} =\sqrt{\frac{K}{m}}

\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}

T=2.1371sec

8 0
3 years ago
Calculate the kinetic energy of a 1 kg object moving at 4.5 ms. Round to the first decimal.
harina [27]

Answer:

91.21

Explanation:

Kinetic energy =1/2 mv2 substitute the values I. E 1/2 *1 *4.5^2= 91.21

8 0
3 years ago
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