Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency ( 
) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
= 
where :
comparing the general form with the given equation
= 18.2329
hence the short period oscillation frequency ( 
) = 0.063 rad/sec
phugoid oscillations natural frequency ( ) = 4.27 rad/sec
Answer:
1.029
Explanation:
1.0090 can also be looked at as "1.009"
0.02 can also be looked at as "0.020"
I think of it as 20+9 which is 29. There for your answer should be 1.029. There are no measurement rules applying to this equation since they are both in centimeters. So you don't have to convert anything.
Hi! The answer is ‘B’! Because the nucleus is found at the center and contains protons (positive charge) and neutrons (no charge)
Answer:
See explanation below
Explanation:
The equation to use for this is the following:
dU = q + w
As the heat is being release, this value is negative, and same here happens with the work done, because it's in the surroundings.
Therefore the change in the energy would be:
dU = -2.59x10^4 - 6.46^4
dU = -9.05x10^4 kJ
Because the Earth rotates through two tidal bulges every lunar day.
