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Lorico [155]
3 years ago
7

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
B, it has a drop, so it is going to increase in speed
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An ideal spring obeys Hooke’s law, F~ = −k~x. A mass of 0.50 kilogram hung vertically from this spring stretches the spring 0.07
masha68 [24]

The spring constant is 66.7 N/m

Explanation:

First of all, we have to find the magnitude of the force acting on the spring. This is equal to the weight of the mass hanging on the spring, which is:

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where:

m = 0.50 kg is the mass of the object

g=10 m/s^2 is the acceleration of gravity

Substituting,

F=(0.50)(10)=5 N

Now we can use Hookes' law to find the constant of the spring:

F=-kx

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Here we have:

F = 5 N

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Therefore, ignoring the negative sign in the formula (which only tells us the direction), we find the spring constant:

k=\frac{F}{x}=\frac{5}{0.075}=66.7 N/m

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BWhat Do You Get When You Multiply An Object's mass times the acceleration?
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I guess but I wanna make sure it’s correct so plz help
Crank
The correct answer is actually D. because rapidly is an adverb of time

I hope I've helped!
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