Distance = Speed × time
Distance = 31m/s × 13 seconds = 403m
The electrostatic force between two charges Q1 and q is given by

where
ke is the Coulomb's constant
Q1 is the first charge
q is the second charge
r is the distance between the two charges
Re-arranging the formula, we have

and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
your answer will be B . becasue light can be transformed into heat .
Answer:

Explanation:
Hello.
In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

The distance is clearly 1743 km and the time is:

Thus, the velocity turns out:

Which is a typical velocity for a plane to allow it be stable when flying.
Best regards.
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