Explanation:
Given that,
The pilot directs the aircraft to fly due north at 600km/h.
A side-wind blows at 100km/h towards the east.
We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :

For direction,

So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.
First you need to find total mechanical energy which is kinetic energy+potential energy, or (1/2mv^2+mgh). Since there is no height, we can pretty much ignore the potential energy and just calculate the kinetic.
1/2mv^2=1/2(64)(3.4)^2= 369.92J. Since it says the speed is 0 at the end of the run, we can assume that all the mechanical energy was lost. Therefore, 369.92 J of energy was lost
Answer:
In Young’s double-slit experiment using monochromatic light, the interference pattern consists of a central <u>MAXIMUM</u>.
Explanation:
In Young's double slit method of experiment we know that on the screen we have light of monochromatic source.
Due to this double slit system when light reaches to the screen there exist a finite path difference on the screen and which will create phase difference between two light reaches on the screen
It is given as
(Path difference)
so here if path difference is zero due to two slits at the center of the screen
Then in that case

so we will have maximum intensity at the center of the screen when light will reach at the center of the screen.
Matter<span> doesn't </span><span>disappear </span>
Hi there!
I believe the answer is transversal or transverse.