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3 years ago

The Tesla Roadster electric car is rated at 16.8kW how much energy does it use during a one hour car drive

Physics

1 answer:

Damm [24]3 years ago

7 0

Answer: $6.05\cdot 10^7 J$

Explanation:

Energy is related to power by:

$E=Pt$

where P is the power and t is the time. In this problem, we have:

$P=16.8 kW=16800 W$

$t=1 h=3600 s$

So, the energy used in one hour is

$E=(16800 W)(3600 s)=6.05\cdot 10^7 J$

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State and prove bessel inequality

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Now, by Pythagoras theorem:

${:\implies \quad \sf \Vert v\Vert^{2}=\Vert v-v_{n}\Vert^{2}+\Vert v_{n}\Vert^{2}}$

${:\implies \quad \displaystyle \sf ||v||^{2}=\Vert v-v_{n}\Vert^{2}+\sum_{i=1}^{n}\vert a_{i}\vert^{2}}$

Now, we can deduce that from the above equation that;

${:\implies \quad \displaystyle \sf \sum_{i=1}^{n}\vert a_{i} \vert^{2}\leqslant \Vert v\Vert^{2}}$

For ${\sf n\to \infty}$ , we have

${:\implies \quad \boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}$

Hence, Proved

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