Answer:
W = 0.562 J
Explanation:
Initial potential energy of two point charges is given as
![U_i = \frac{kq_1q_2}{r_1}](https://tex.z-dn.net/?f=U_i%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7Br_1%7D)
here we have
![q_1 = 3.10 \mu C](https://tex.z-dn.net/?f=q_1%20%3D%203.10%20%5Cmu%20C)
![q_2 = -4.50 \mu C](https://tex.z-dn.net/?f=q_2%20%3D%20-4.50%20%5Cmu%20C)
![r_1 = 0.140 m](https://tex.z-dn.net/?f=r_1%20%3D%200.140%20m)
now we have
![U_i = \frac{(9\times 10^9)(3.10 \mu C)(-4.50 \mu C)}{0.140}](https://tex.z-dn.net/?f=U_i%20%3D%20%5Cfrac%7B%289%5Ctimes%2010%5E9%29%283.10%20%5Cmu%20C%29%28-4.50%20%5Cmu%20C%29%7D%7B0.140%7D)
![U_i = -0.897 J](https://tex.z-dn.net/?f=U_i%20%3D%20-0.897%20J)
now at final position the distance between two charges is given as
![r_2 = \sqrt{0.265^2 + 0.265^2} = 0.375 m](https://tex.z-dn.net/?f=r_2%20%3D%20%5Csqrt%7B0.265%5E2%20%2B%200.265%5E2%7D%20%3D%200.375%20m)
Now final energy is given as
![U_f =\frac{kq_1q_2}{r_2}](https://tex.z-dn.net/?f=U_f%20%3D%5Cfrac%7Bkq_1q_2%7D%7Br_2%7D)
![U_f = \frac{(9\times 10^9)(3.10 \mu C)(-4.50 \mu C)}{0.375}](https://tex.z-dn.net/?f=U_f%20%3D%20%5Cfrac%7B%289%5Ctimes%2010%5E9%29%283.10%20%5Cmu%20C%29%28-4.50%20%5Cmu%20C%29%7D%7B0.375%7D)
![U_f = -0.335 J](https://tex.z-dn.net/?f=U_f%20%3D%20-0.335%20J)
Now the work done to change the position of charge is given as
![W = U_f - U_i](https://tex.z-dn.net/?f=W%20%3D%20U_f%20-%20U_i)
![W = (-0.335) - (-0.897) = 0.562 J](https://tex.z-dn.net/?f=W%20%3D%20%28-0.335%29%20-%20%28-0.897%29%20%3D%200.562%20J)
Answer:
58.37 V
Explanation:
Given that
Number of winding on coil, N = 80 turns
Area of the coil, A = 25 cm * 40 cm = 0.25 m * 0.4 m
Magnitude of magnetic force, B = 1.1 T
Time of rotation, t = 0.06 s
See the attachment for calculations
Answer:
You didn't give the information needed for the answer bud
Explanation:
With what you do need help?????