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larisa86 [58]
3 years ago
7

The Tesla Roadster electric car is rated at 16.8kW how much energy does it use during a one hour car drive

Physics
1 answer:
Damm [24]3 years ago
7 0

Answer: 6.05\cdot 10^7 J

Explanation:

Energy is related to power by:

E=Pt

where P is the power and t is the time. In this problem, we have:

P=16.8 kW=16800 W

t=1 h=3600 s

So, the energy used in one hour is

E=(16800 W)(3600 s)=6.05\cdot 10^7 J

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Autotrophic plants do not require which of the following? solar energy carbon dioxide water oxygen NextReset
alukav5142 [94]
<span>Autotrophic plants do not require "Oxygen" as it is a waste product of the process of photosynthesis which they do.

In short, Your Final Answer would be Option D

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4 0
3 years ago
Rocks are elastic too! Explain how elasticity and Harry Reid's elastic rebound theory lead to a better understanding of earthqua
ANEK [815]
After the great 1906 San Francisco earthquake, geolophysicistHarry Fielding Reid examined the displacement of the ground surface along the San Andreas Fault. He concluded that the quake must have been the result of the elastic reboundof the strain energy in the rocks on either side of the fault.
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There is a lot of force and a bit of compression when rocks squash up against other rocks causing earthquakes
7 0
3 years ago
A cart loaded with bricks has a total mass of 22.2 kg and is pulled at constant speed by a rope. The rope is inclined at 27.5 ◦
musickatia [10]

Answer:

W = 1.432 KJ

Explanation:

given,

mass = 22.2 Kg

angle of the rope = 27.5°

distance on the ground = 24 m

kinetic friction= μ = 0.32

acceleration due to gravity, g = 9.8 m/s²

Work done = ?

W = F d cosθ

a = 0 because it is moving with constant speed

equating all the forces acting  in x direction

F cosθ = F friction = μN  

equating all the forces acting  in y direction

F sinθ + N -mg =0

now,

N = mg - F sinθ

putting value of N

F cosθ = μ mg -μ F sinθ

F (cosθ + μsinθ ) = μ mg

F = \dfrac{\mu mg}{cos\theta + \mu sin\theta}

F = \dfrac{0.32 \times 22.2 \times 9.8}{cos 27.5^0+0.32 \times sin27.5^0}

F =67.28 N

now,

W=F d cosθ

W =67.28 x 24 x cos(27.5)

W =1432.27 J

W = 1.432 KJ

7 0
3 years ago
Read 2 more answers
An automobile engine delivers 47.4 hp. how much time will it take for the engine to do 6.82 × 105 j of work? one horsepower is e
kogti [31]
1 horsepower is equal to 746 W, so the power of the engine is
P=47.4 hp \cdot 746  \frac{W}{hp}=35360 W
The power is also defined as the energy E per unit of time t:
P= \frac{E}{t}
Where the energy corresponds to the work done by the engine, which is E=6.82 \cdot 10^5 J. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
t =  \frac{E}{P}= \frac{6.82 \cdot 10^5 J}{35360 W}=19.3 s
8 0
3 years ago
Calculate the pressure exerted on the heel of a boy’s foot if the boy weighs 80 N and he lands on one heel,which has an area of
cricket20 [7]

Pressure at a given surface is given as ratio of normal force and area

so here force due to heel of the shoes is given as 80 N

and the area of the heel is given as 16 cm^2

so we can say

P = \frac{F}{A}

here we have

F = 80 N

A = 16 cm^2 = 16 * 10^{-4} m^2

P = \frac{80}{16 * 10^{-4}}

P = 5 * 10^4 N/m^2

so pressure at the surface due to its heel will be 5 * 10^4 N/m^2

3 0
3 years ago
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