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Ganezh [65]
3 years ago
10

Ionic and covalent bonds help arrange atoms into unique structures for proteins like hemoglobin. Why is this necessary? (1 point

)
a. The ionic bonds alone in a protein help determine its function

b. The structure of a protein allows it to carry out its unique function.

c. The bonds help hold the protein together but are unrelated to the function

d. The structure of the protein allows it to carry out whatever function is needed the most
Chemistry
2 answers:
Reptile [31]3 years ago
7 0

Ionic and covalent bonds help arrange atoms into unique structures for proteins like hemoglobin. This is necessary because:

  • <u>B. The structure of a protein allows it to carry out its unique function.</u>

A covalent bond is one that comes together as a result of two atoms both use an electron.

An ionic bond is a bond that is formed when two oppositely charged ions come together in a compound.

As a result of this, these two bonds helps to arrange atoms into unique structures because they help to link amino acids in a protein chain like hemoglobin and they help to determine the structure of this protein.

Therefore, the correct answer is option B

Read more here:

brainly.com/question/14062466

Contact [7]3 years ago
3 0
B. Is the correct answer
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Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce
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The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca^{2+}(aq) and 0.0390 M Ag^{+}(aq). What will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate? What percentage of the Ca^{2+}(aq) can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

      Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}

[Ag^{+}] = 0.0390 M

When Ag_{2}SO_{4} precipitates then expression for K_{sp} will be as follows.

         K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]

        1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]

       [SO^{2-}_{4}] = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

         CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}

      K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

     4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788

           [Ca^{2+}] = 0.00625 M

Now, we will calculate the percentage of Ca^{2+} remaining in the solution as follows.

               \frac{0.00625}{0.05} \times 100

                 = 12.5%

And, the percentage of Ca^{2+} that can be separated is as follows.

                     100 - 12.5

                     = 87.5%

Thus, we can conclude that 87.5% will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate.

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