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oksian1 [2.3K]
2 years ago
14

Using the paths below assume that the distance from Selma to Decatur is 40.9km. How far is it from Selma to Alexander city?

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
8 0

Answer:

sorry po hindi ko po alam

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MIDDLE SCHOOL MATH- 4 QUESTIONS
Contact [7]

Answer:

( I am assuming that these are all fractions)

1. 14 \frac{4}{7}

2.  8

3. \frac{4}{15}

4. 5 \frac{8}{11}

Step-by-step explanation:

1. First you have to convert 15 into a fraction but it must have the same denominator causing the equation to look like 105/7 - 3/7= 102/7. But you cannot just leave the fraction like that it must be simplified 14 \frac{4}{7}

2. Three-fifths of an hour is 36 minutes. You would next multiply 5 by 60 which would the hours into minutes 5 x 60 = 300. You would then divide 300 by 36 which would give you 8.3333333333, which I just simplified it to 8

3. In order for you to multiply a fraction you would first multiply the top then the bottom. 12 x 6= 72, 15 x 18= 270. The fraction would look like 72/270 which is simplified to \frac{4}{15} .

4. First I changed the fractions into improper fractions causing the fraction to look like 36/8 x 14/11 (I got these answers by 8 by 4 then adding 4, then for the next fraction I multiplied 11 by 1 then added 3.) 36 x 14= 1224, 11 x 8= 88 the fraction would look like 1,224/88 you would simplify to 5 \frac{8}{11}

Hope this helps

Please tell me if I made any mistakes I enjoy learning from them.

6 0
3 years ago
In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the
Sidana [21]

Step 1    

<u>Find the value of TS</u>

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

\frac{TR}{TP} =\frac{TS}{QT}

solve for TS

TS =\frac{TR*QT}{TP}

we have

RP=2\ cm\\TP=18\ cm\\QT=27\ cm

TR=TP+RP\\TR=18+2=20\ cm

substitute

TS =\frac{20*27}{18}  

TS =30\ cm

Step 2

<u>Find the value of SQ</u>

we know that

SQ=TS-QT

we have

TS =30\ cm

QT=27\ cm

substitute

SQ=30\ cm-27\ cm=3\ cm

therefore

<u>the answer is</u>

the value of SQ is 3\ cm

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3 years ago
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Rectangle ABCD is similar to rectangle EFGH. Side CD is proportional to side ___.
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If the rectangle ABCD is similar to rectangle EFGH, side CD is proportional to the side

C. GH

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