Answer:
S(x) = x² + 390224/x
Step-by-step explanation:
Volume of the open box = V = 97556 cm³
Material needed:
Let´s call x the side of the square base then the area of the base is
A(b) = x²
For the sides of the box, we have 4 sides each one with area of x*h
where h is the height of the box
The volume of the box V(b) = 97556 = x²*h then h = 97556/x²
S(x,h) = x² + 4*x*h*
The surface area of the box as function of x is:
S(x) = x² + 4*x*97556/x²
S(x) = x² + 390224/x
Answer:
a = -4, b = 3 and c = 6 (OR)
a = -4, b = -3 and c = 6
Step-by-step explanation:
Add 16 to both sides.
or 
or 
or 
Therefore, a = -4, b = 3 and c = 6 (OR)
a = -4, b = -3 and c = 6
1. Eyeballing the data, the best fit will be pretty close to a line between the leftmost point and the rightmost point.
We estimate those points as (4,220) and (28,470)
The point point form for a line joining (a,b) and (c,d) is
(c-a)(y-b) = (d-b)(x-a)
(28 - 4)(y - 220) = (470 - 220)(x - 4)
24(y - 220) = 250(x-4)
24y - 5280 = 250x - 1000
24y = 250 x + 4280
y = (250/24) x+ (4280/24)
Approximately that's,
y = 10.4 x + 178
Answer: 4th choice, 10.4x + 180
2. For 48 wheelbarrows,
y = 10.4(48)+180 = 679.2
Answer: 679.2 liters of sand
Answer:
Function:
c = f(w) = 0.49, 0 < w ≤ 1
= 0.70, 1 < w ≤ 2
= 0.91, 2 < w ≤ 3
Step-by-step explanation:
Yes, the relation described can be interpreted as a function.
Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.
As described in the question, the relation can be expressed as a function.
c can be expressed as a function of w in the following manner:
c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable
c = f(w) = 0.49, 0 < w ≤ 1
= 0.70, 1 < w ≤ 2
= 0.91, 2 < w ≤ 3
where, c is in dollars and w is in ounces.
