Answer: nickels = 14, dimes = 42, quarters = 18
<u>Step-by-step explanation:</u>
Let n represent nickels <em>which has a value of $0.05 </em>
Let d represent dimes <em>which has a value of $0.10</em>
Let q represent quarters <em>which has a value of $0.25</em>
It is given that:
n = n
d = 3n
q = n + 4
and their total value is $9.40 ⇒ n + d + q = $9.40
Use substitution to find the quantity of nickels:
.05(n) + .10(3n) + .25(n + 4) = 9.40
5n + 10(3n) + 25(n+4) = 940 <em>multiplied by 100 </em>
5n + 30n + 25n + 100 = 940 <em>distributed</em>
60n + 100 = 940 <em>added like terms</em>
60n = 840 <em>subtracted 100</em>
n = 14 <em>divided by 60</em>
n = 14
d = 3n
= 3(14)
= 42
q = n + 4
= (14) + 4
= 18
Answer:
Step-by-step explanation:
x is at (0, 4)
5x - 11 < -11
5x < 0
x < 0
4x + 2 > 14
4x > 12
x > 3
x<0 or x > 3
