A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
1 answer:
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Answer:
Impulse is 1.239 kg.m/s in upward direction
Explanation:
Taking upward motion as positive and downward motion as negative.
Downward motion:
Given:
Mass of ball (m) = 0.150 kg
Displacement of ball (S) = -1.25 m
Initial velocity (u) = 0 m/s
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is downward, final velocity must be negative. So,
Upward motion:
Given:
Displacement of ball (S) = 0.665 m
Initial velocity () = 4.95 m/s(Upward direction)
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is upward, final velocity must be positive. So,
Now, impulse is equal to change in momentum. So,
Impulse = Final momentum - Initial momentum
Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.