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oee [108]
3 years ago
8

A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?

Physics
1 answer:
Katyanochek1 [597]3 years ago
7 0

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

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The electric field 30cm from a van de Graaff generator is measured to be 28,300N/C. What is the charge of the van de Graaf?
gizmo_the_mogwai [7]

Answer:

14

Explanation:

EWAN KO LANG DIN BASTA YAN ALAM KO

8 0
2 years ago
A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is
LenaWriter [7]

Answer:

0.2

Explanation:

F= BIL sin©

3= B×10×1.5 sin90

B=3/15

B= 0.2

8 0
2 years ago
From the center of the Earth to the moon, what should the orbital radius of such satellite be in order to stay over the same poi
yulyashka [42]

In order to have a period that matches the Earth's rotation, a satellite must be in a circular orbit, and 42,164 km from the center of the Earth.

But that's not quite enough to make sure that it always stays over the same point on the Earth's surface (and appears motionless in the sky). For that to happen, the satellite's orbit has to be directly over the Equator.

The Moon has nothing to do with any of this.

3 0
3 years ago
An elevator filled with passengers has a mass of 1683 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 f
artcher [175]

Answer:

the tension is 18513N

Explanation:

Given that

mass = 1683kg

acceleration = 1.2m/s^2

acceleration due to gravity = 9.8m/s^2

T-mg =   ma

T = ma + mg

T = m(a +g)

T = 1683 kg(1.20 m/s2 + 9.8)

T = 1683 (11)

T = 18513N

therefore, the tension is 18513N

4 0
3 years ago
Read 2 more answers
The quantity of charge passing through a surface of area 1.82 cm2 varies with time as q = q1 t 3 + q2 t + q3 , where q1 = 5.2 C/
Brrunno [24]

Answer:

Current through the surface at t = 1.1 s is 21.37 A.

Explanation:

The charge is passing through a surface of area varies with time as :

q=q_1t^3+q_2t+q_3

Here,

q_1=5.2\ C/s^3\\\\q_2=2.5\ C/s\\\\q_3=6.5\ C

t is in seconds

q=5.2t^3+2.5t+6.5

The rate of change of electric charge is called electric current. It is given by :

I=\dfrac{dq}{dt}\\\\I=\dfrac{d(5.2t^3+2.5t+6.5)}{dt}\\\\I=15.6t^2+2.5

At t = 1.1 s, Current,

I=15.6(1.1)^2+2.5\\\\I=21.37\ A

So, the instantaneous current through the surface at t = 1.1 s is 21.37 A.

3 0
3 years ago
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