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pantera1 [17]
2 years ago
11

The driver of a 1,500 kg car is traveling at 25 m/s. A deer runs into the road and the driver slams on the brakes. If it takes t

he car 5 seconds to stop, the acceleration of the car is ____ m/s2.
a.
0.25 m/s2


b.
-0.25 m/s2


c.
5 m/s2


d.
-5 m/s2
Physics
1 answer:
Aliun [14]2 years ago
8 0

Answer:

c.

5 m/s2

Explanation:

Δv = at

a = Δv/t

a = (0 - 25)/5

a = 5 m/s²

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Angelina_Jolie [31]
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You are on a Parkour course. First you climb a angled wall up 9.5 meters. They you shimmy along the edge of a 3.5 meter long wal
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Average speed = (total distance covered) / (time to cover the distance)

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3 years ago
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You have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3
jeka57 [31]

Answer:

W = 0J

Explanation:

The work done by the dresser is described as

W = f d (cos θ)

F has been given as the weight of this dresser. And it is 3500 N

d = 0 m

When you put these values into the equation

W = 3500 x 0 x cosθ

W = 0 J

This value tells us that the work done on this dresser is zero. No work has been done. Therefore the last option answers the question.

3 0
3 years ago
A 50 kg laboratory worker is exposed to 30 mJ of neutron radiation with an RBE of 10. Part A What is the dose in mSv
lys-0071 [83]

Answer:

The dose is 6 mSV

Explanation:

The absorbed dose (in gray - Gy) is the amount of energy that ionizing radiation deposits per unit mass of tissue. That is,

Absorbed dose = Energy deposited / Mass

while Dose equivalent (DE) (in Seivert -Sv) is given by

DE = Absorbed dose × RBE (Relative biological effectiveness)

First, we will determine the Absorbed dose

From the question, Energy deposited = 30mJ and Mass = 50kg

From,

Absorbed dose = Energy deposited / Mass

Absorbed dose = 30mJ/50kg

Absorbed dose = 0.6 mGy

Now, for the Dose equivalent (DE)

DE = Absorbed dose × RBE

From the question, RBE = 10

Hence,

DE = 0.6mGy × 10

DE = 6 mSv

5 0
3 years ago
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