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pantera1 [17]
2 years ago
11

The driver of a 1,500 kg car is traveling at 25 m/s. A deer runs into the road and the driver slams on the brakes. If it takes t

he car 5 seconds to stop, the acceleration of the car is ____ m/s2.
a.
0.25 m/s2


b.
-0.25 m/s2


c.
5 m/s2


d.
-5 m/s2
Physics
1 answer:
Aliun [14]2 years ago
8 0

Answer:

c.

5 m/s2

Explanation:

Δv = at

a = Δv/t

a = (0 - 25)/5

a = 5 m/s²

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Answer:

b

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2 years ago
What average force is required to stop a 980 kg car in 9.0 s if the car is traveling at 91 km/h ?
kozerog [31]
Newton's second law of motion:
F=ma
a =  \frac{v}{t}
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v = 91 \div 3.6
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Then a is:
a =  \frac{25.3}{9}
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3 years ago
A metallic wire has a diameter of 4.12mm. when the current in the wire is 8.00a, the drift velocity is 5.40×10−5m/s.
Darina [25.2K]
R = 2.06 mm = 2.06 x 10^(-3) m
Q = 1.6 x 10^(-19) C
v = 2.5 x 10^(-5) m/s
I = 8 A = 8 C/s
A = r² π = ( 2.06 x 10^(-3) ) ² x 3.14 = 13.325 x 10^(-6 ) m² =
= 1.3325 x 10^(-5) m²
I = n Q v A
n = I / (Q v A)
n = 8 C/s / ( 1.6 x 10 ^(-19) * 5.4 x 10^(-5) * 1.3325 x 10^(-5) ) = 
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8 0
3 years ago
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Estimate the average force that a baseball pitcher's hand exerts on a 0.145-kg baseball as he throws a 40-m/s pitch. Assume the
Kitty [74]

Answer:

38.67 N

Explanation:

v = Final velocity = 40 m/s

u = Initial velocity

m = Mass of ball = 0.145kg

s = Displacement of ball = 3 m

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{40^2-0^2}{2\times 3}=\frac{800}{3}\ m/s^2

F=ma

\\\Rightarrow F=0.145\times \frac{800}{3}\\\Rightarrow F=38.67\ N

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