Speed=Distance/Time
Distance=40m,time=5.79seconds
S=40/5.79
=6.908m/s
Answer:
1.8m
Explanation:
Let the Elastics of the steel ASTM-36 
The strain of the bar when subjected to 150 MPa is
Therefore, if the bar elongates by 1.35 mm, then the original length L would be:
or 1.8m
The answer is A.number of protons in the nucleus.
Answer:
when the mass of the bottle is 0.125 kg, the average height of the beanbag is 0.35 m.
when the mass of the bottle is 0.250 kg, the average maximum height of the beanbag is 0.91m.
when the mass of the bottle is 0.375 kg, the average maximum height of the beanbag is 1.26m.
when the mass of the bottle is 0.500 kg, the average maximum height of the beanbag is 1.57m.
Explanation:
Answer:
(a) T = 10 s
(b) f = 0.1 Hz
(c) λ = 32 m
(d) v = 3.2 m/s
(e) Insufficient data
Explanation:
(a)
Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:
T = Period = Time Taken/No. of Waves
T = 50 s/5
<u>T = 10 s</u>
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(b)
Frequency is the reciprocal of time period:
f = frequency = 1/T
f = 1/10 s
<u>f = 0.1 Hz</u>
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(c)
Wavelength is the distance between two consecutive crests or troughs:
<u>λ = Wavelength = 32 m</u>
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(d)
Speed of wave is given by the following formula:
Speed = v = fλ
v = (0.1 Hz)(32 m)
v = 3.2 m/s
(e)
Amplitude cannot be found with given data.
