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creativ13 [48]
2 years ago
9

Factor the expressions Please help

Mathematics
2 answers:
adelina 88 [10]2 years ago
6 0

Answer:

(x + 1)( {6x }^{2}  - 2x)

telo118 [61]2 years ago
6 0
(X+1)(6x^2-2x)
2x(x+1)(3x-1)
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We have been given the function y=e^{4x}

We know that the range is set of y values for which the function is defined. Therefore, we will find the value for x and then observe the restriction is y's values.

y=e^{4x}\\\ln y = \ln (e^{4x})\\\ln y =4x\\x=\frac{1}{4}\ln y

Now, we know that logarithm function is not defined for negative values. Hence, the value for y is always greater than zero.

Therefore, the range of the function is given by y>0

B is the correct option.

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W=17 im too good at math to be wrong about this
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