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Answer:
25 +0i
Step-by-step explanation:
The conjugate of a complex number is that number with the sign of the imaginary part reversed.
For z = -3+4i, its conjugate z* is -3-4i. The product of z and z* is ...
(-3 +4i)(-3 -4i) = -3(-3 -4i) +4i(-3 -4i)
= 9 +12i -12i -16i² = 9 +16 = 25
The real part of the product is 25; the imaginary part is 0.
(-3 +4i)(-3 -4i) = 25 +0i
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You may have noticed that (z)(z*) = |z|², the sum of the squares of the real and imaginary parts. It is always a non-negative real number.
Step-by-step explanation:
Im not sure if its supposed y = -2x + 1 or y = 2x + 1 but I'll solve the problem for both.
First for y = -2x + 1
Since the line has to be parallel to y = -2x + 1
the slopes would be the same.
so, so far the equation would be
y = -2x + b
now we substitute (5,2) into the equation
2 = -2(5) + b
2 = -10 + b (Add 10 to both sides of the equation)
+10 +10
12 = b
Now that we solved for b
The equation would be
y = -2x + 12
^^ This equation is parallel to y = -2x + 1
Now to solve for an equation parallel to y = 2x + 1
Both equations would have the same slope
So far we would have
y = 2x + b
Now we solve for be by substituting the point (5,2)
2 = 2(5) + b
2 = 10 + b (subtract 10 from both sides)
-10 -10
-8 = b
After solving for b
The equation is
y = 2x - 8
This equation is parallel to y = 2x + 1
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