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pochemuha
3 years ago
6

HELLP THIS IS EASY 8TH GRADE STUFF BUT

Mathematics
1 answer:
Ket [755]3 years ago
7 0

Answer:

6/14

Step-by-step explanation:

you need to just divide the denominator and numerator by 5. 30 / 5 is 6 and 70 / 5 is 14 so your answer is 6 / 14.

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What is the slope of the line passing through the points (7, 10) and (5, 16) ?<br> Thank you
butalik [34]

Answer:

m=-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=16-10/5-7

m=6/-2

m=-3

4 0
2 years ago
. Laura and Alicia both exercise 5 days a week. Laura exercises for 30 minutes each day. Alicia exercises for 45 minutes each da
statuscvo [17]

Answer: 1 hour 15 minutes

Step-by-step explanation:

From the question, we are informed that Laura and Alicia both exercise 5 days a week and that Laura exercises for 30 minutes each day. For the 5 days, she'll exercise for:

= 5 × 30 minutes

= 150 minutes

= 2 hours 30 minutes

Alicia exercises for 45 minutes each day. Fir the 5 days, she'll exercise for:

= 5 × 45 minutes

= 225 minutes

= 3 hours 45 minutes

We then calculate the difference in their exercise per week which will be:

= 3 hours 45 minutes - 2 hours 30 minutes

= 1 hour 15 minutes

6 0
2 years ago
NEED HELP PLEASE!!!! (10 PTS)
slavikrds [6]
Tigers:-

f(t)  = 7(1 + 0.1)^2   where t = number of years

Eagle 

g(t)  =  15 + 2t


B  after ten year  number tigers = f(t) = 7(1 + 0.1)^10  =   18

  number of eagles = 15 + 10(2) = 35

C when the number of tigers = number eagles the 2 functions will be equal;-

f(t) = g(t)  that is:-

7* 1.1^t  = 15 + 2t

solve for t
5 0
3 years ago
The rabbit population in a certain area is 200% of last year's population.There are 1,000 rabbits this year.how many were there
alexandr1967 [171]

the answer is 200%x=1000 which is =500 when you divide 1000 by 2.  So 500 rabbits last year

8 0
3 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
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