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lord [1]
3 years ago
5

How far can you get away from your little sister with a squirt gun filled with paint if you can travel at 3 m/s and you have 15s

before she sees you?
Physics
1 answer:
Kay [80]3 years ago
5 0
It would be what 3•15 is so that's 45 m i think
You might be interested in
Pls help me this is being timed. pls.
ahrayia [7]

Answer:

10N each

Explanation:

Doing a little math here to make it balanced. 10+10=20 therefore you have the same on both sides.

Hope this helps!

6 0
3 years ago
The relationship between energy (E), power (P), and time (t) is
NemiM [27]

Answer:

The avarage power of the body is 96.898 watts.

Explanation:

We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that E = 2000\,Cal and t = 1\,day, the power of body, measured in watts, is:

P = \frac{(2000\,Cal)\cdot \left(4186\,\frac{J}{Cal} \right)}{(1\,day)\cdot \left(24\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h} \right)}

P = 96.898\,W

The avarage power of the body is 96.898 watts.

3 0
4 years ago
how long does it take an acorn to hit the ground after dropping from the branch of a tree 12.5 m high?
Grace [21]
The right formula to use is: T^2= 2d/g
where T= time taken
d = 12.5m
g = is a constant and is equal to 9.8m/s
therefore, T^2 = 2*12.5/9.8 
Using the values above, the time taken for the acorn to reach the ground is 1.59 second
T = 1.59 S
6 0
4 years ago
A large 2.3 kg bird, searching for food, spots a large, 0.391 kg bug hovering in its vicinity. If the bird is traveling at 8.2 m
aleksandr82 [10.1K]

Your answer is 7.009m/s

If you would like to show how I solved this just ask. :)

Hope this helps -John

8 0
3 years ago
What potential difference is needed to stop an electron that has an initial velocity v=6.0
Assoli18 [71]

Formula for kinetic energy of an object:

KE = 0.5mv²

m is the mass and v is the velocity.

Formula for the work done on a charged object by moving it through a potential difference:

W = ΔVq

ΔV is the potential difference and q is the charge of the object.

To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:

W = KE

Substitute W = ΔVq and KE = 0.5mv²

ΔVq = 0.5mv²

Given values:

q = 1.6×10⁻¹⁹C

m = 9.11×10⁻³¹kg

v = 6.0m/s

Plug in the given values and solve for ΔV

ΔV×1.6×10⁻¹⁹ = 0.5×9.11×10⁻³¹×6.0²

ΔV = 1.02×10⁻¹⁰V

7 0
3 years ago
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