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Bad White [126]
2 years ago
15

HELP!!!!!!!!!!!!!! ILL GIVE BRAINILIST

Mathematics
1 answer:
Scorpion4ik [409]2 years ago
5 0

\frac{1}{3}  \div  \frac{4}{5}  \\ \\  \frac{1}{3}  \times  \frac{5}{4}  \\  \\   \frac{1 \times 4}{3 \times 4}  \times  \frac{5 \times 3}{4 \times 3}  \\  \frac{4}{12}  \times  \frac{15}{12}  \\  \frac{4 \times 5}{12}  \\  \frac{60}{12}  \\ 5  \: \:  \:  \: answer

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In the parallelogram below, z = ?°
katrin [286]

Answer:

z is 111 degrees

Step-by-step explanation:

69 ° and z is a linear pair, therefore:

69 + z = 180

z = 180 - 69

z= 111

7 0
3 years ago
I WILL MARK BRAINLIEST!!
vagabundo [1.1K]

Answer:

4 days a week

Step-by-step explanation:

2+1=3

3+1/2+12=4

4 0
3 years ago
Read 2 more answers
A 2-column table with 4 rows. Column 1 is labeled Size of Container with entries 12 ounces, 16.3 ounces, 28 ounces, 64 ounces. C
Jobisdone [24]

Answer:

12 oz: $0.35 per oz

16.3 oz: $0.38 per oz

28 oz: $0.30 per oz

64 oz: $0.33 per oz

Which size is the best deal?

28 oz

Step-by-step explanation: it gave me the right answer after.

5 0
3 years ago
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One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

6 0
3 years ago
I have a Brainliest
yawa3891 [41]
When you apply for a loan, the lender will verify your income. They want to be sure you were able to make the payment owed to them.

When you link your loan to an asset, it is called a secured loan. This means that you offer an item of value to the lender just in case you're not able to make your payments.
4 0
3 years ago
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