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Bad White [126]
2 years ago
15

HELP!!!!!!!!!!!!!! ILL GIVE BRAINILIST

Mathematics
1 answer:
Scorpion4ik [409]2 years ago
5 0

\frac{1}{3}  \div  \frac{4}{5}  \\ \\  \frac{1}{3}  \times  \frac{5}{4}  \\  \\   \frac{1 \times 4}{3 \times 4}  \times  \frac{5 \times 3}{4 \times 3}  \\  \frac{4}{12}  \times  \frac{15}{12}  \\  \frac{4 \times 5}{12}  \\  \frac{60}{12}  \\ 5  \: \:  \:  \: answer

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andriy [413]

Step-by-step explanation:

I'll do 2.

Alright,Alex let say we have factored a quadratic into two binomial, for example

(5x + 3)(6x - 4)

If we set both of those equal to zero

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We can used the zero product property in this case to find the roots of the quadratic equation.

This means that

if  \: ab = 0 \: then \: a = 0 \: and \: b = 0

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So our roots are negative 3/5 and negative 2/3 using zero product property

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Hi there!

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