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enot [183]
3 years ago
7

55 less than 1/3 of the number is 31

Mathematics
2 answers:
kati45 [8]3 years ago
6 0
False. 1/3 of 31 is about 10, so 55 is bigger than 10
adelina 88 [10]3 years ago
4 0

Answer:

n=258

Step-by-step explanation:

1/3n-55=31

+55 to both sides

1/3n=86

divide 1/3 both sides

n=86/1 ÷1/3

we flip fraction when divide and multiply

86/1×3/1 =258

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If the diameter of a circle is 5, what is its circumference?
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Multiply the diameter by PI which is 3.14 so that means the circumference would be 15.7.

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X^2+2x+1 is a perfect square trinomial <br><br> True of False?
Nimfa-mama [501]

Answer:

True.

Step-by-step explanation:

It is because it is in the form a^2x^2+2abx+b^2 and this equals (ax+b)^2.

Why it is in that form:  well comparing  a^2x^2+2abx+b^2, we have a=1, b=1. Testing, plug in those values:

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This has the squared form of (x+1)^2.

Test if you like:

(x+1)^2

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x^2+2x+1

It does indeed equal.

4 0
3 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

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