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viva [34]
3 years ago
12

Supply the missing dollar amounts for each of the following independent cases

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

The table is an illustration of inventory.

The missing dollar amounts of the table will be calculated using the following set of formula

\mathbf{Cost\ of\ goods\ available\ for\ sale - Ending\ inventory = Cost\ of\ Goods\ sold}

\mathbf{Sales - Cost\ of\ goods\ sold = Gross\ Profit}

\mathbf{Beginning\ Inventory + Purchases = Cost\ of\ goods\ available\ for\ sale}

<u>Case A</u>

Calculate cost of ending inventory using:

\mathbf{Cost\ of\ goods\ available\ for\ sale - Ending\ inventory = Cost\ of\ Goods\ sold}

So, we have:

\mathbf{\$2100 - Ending\ inventory = \$920}

\mathbf{Ending\ inventory = \$2100 - \$920}

\mathbf{Ending\ inventory = \$1180}

Calculate the gross profit using:

\mathbf{Sales - Cost\ of\ goods\ sold = Gross\ Profit}

So, we have:

\mathbf{\$1300 - \$920 = Gross\ Profit}

\mathbf{Gross\ Profit = \$380 }

<u>Case B</u>

Calculate cost of goods sold using:

\mathbf{Cost\ of\ goods\ available\ for\ sale - Ending\ inventory = Cost\ of\ Goods\ sold}

So, we have:

\mathbf{\$2200 - \$720 = Cost\ of\ Goods\ sold}

\mathbf{Cost\ of\ Goods\ sold = \$1480}

Calculate the gross profit using:

\mathbf{Sales - Cost\ of\ goods\ sold = Gross\ Profit}

So, we have:

\mathbf{\$1500 - \$1480 = Gross\ Profit}

\mathbf{Gross\ Profit = \$20 }

<u>Case C</u>

Calculate sales revenue using:

\mathbf{Sales - Cost\ of\ goods\ sold = Gross\ Profit}

So, we have:

\mathbf{Sales - \$800= \$1000}

\mathbf{Sales = \$1800}

Calculate cost of goods available for sale using:

\mathbf{Cost\ of\ goods\ available\ for\ sale - Ending\ inventory = Cost\ of\ Goods\ sold}

So, we have:

\mathbf{Cost\ of\ goods\ available\ for\ sale - \$900 = \$800}

\mathbf{Cost\ of\ goods\ available\ for\ sale = \$1700}

Next, we calculate the purchases using:

\mathbf{Beginning\ Inventory + Purchases = Cost\ of\ goods\ available\ for\ sale}

So, we have:

\mathbf{\$700 + Purchases = \$1700}

\mathbf{Purchases = \$1000}

<u>Case D</u>

Calculate the cost of goods available for sale using:

\mathbf{Cost\ of\ goods\ available\ for\ sale - Ending\ inventory = Cost\ of\ Goods\ sold}

So, we have:

\mathbf{Cost\ of\ goods\ available\ for\ sale - \$850 = \$1250}

\mathbf{Cost\ of\ goods\ available\ for\ sale = \$2100}

Calculate beginning inventory using:

\mathbf{Beginning\ Inventory + Purchases = Cost\ of\ goods\ available\ for\ sale}

So, we have:

\mathbf{Beginning\ Inventory + \$1200 = \$2100}

\mathbf{Beginning\ Inventory = \$3300}

Calculate Gross Profit using:

\mathbf{Sales - Cost\ of\ goods\ sold = Gross\ Profit}

So, we have:

\mathbf{\$1420 - \$1250 = Gross\ Profit}

\mathbf{Gross\ Profit = \$170}

<u>Case E</u>

Calculate cost of goods sold using:

\mathbf{Sales - Cost\ of\ goods\ sold = Gross\ Profit}

So, we have:

\mathbf{\$1600 - Cost\ of\ goods\ sold = \$1120}

\mathbf{Cost\ of\ goods\ sold = \$480}

Calculate cost of ending inventory using:

\mathbf{Cost\ of\ goods\ available\ for\ sale - Ending\ inventory = Cost\ of\ Goods\ sold}

So, we have:

\mathbf{\$2150 - Ending\ inventory = \$480}

\mathbf{ Ending\ inventory = \$1670}

Read more about inventory at:

brainly.com/question/15118949

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Then
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From the above deduction, it can be deduced that the correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your desired help.
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Answer:

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Step-by-step explanation:

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3 years ago
Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
umka2103 [35]

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

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7. A game is played with 2 fair number cubes. One cube has faces numbered 1 through 6. The second number cube is numbered 4 thro
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Answer:

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Step-by-step explanation:

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What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)

The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.

However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.

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