The car traverses a distance  after time
 after time  according to
 according to

where  is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is
 is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is

5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity  after 2 s of travel is given by
 after 2 s of travel is given by

which makes C the most likely answer.
 
        
             
        
        
        
Assuming there is no force of friction... 
F = ma 
F = (1300kg)(1.5m/s^2) 
F = 1950N
Just multiply mass by acceleration. 
1300 x 1.5 = 1950N.
        
             
        
        
        
Make the base of the building zero. Then the initial distance is 100m, final distance unknown x. Use gravity, time and initial velocity to solve for final distance. 
x - 100 = (0)(5) +(1/2)(-9.81)(5^2)
x - 100 = 0 - 122.625
x = -122.625 + 100
x = -22.625 m below ground
        
             
        
        
        
Answer:
= 4.38 × 10³⁴kgm²/s
Explanation:
Given that,
mass of moon m = 9.5 × 10²²kg
Orbital radius r = 4.28  × 10⁵km
Orbital period  T = 28.9days
T = 28.9  × 24 × 60 × 60
    = 2,496,960s
Angular momentum of the moon about the planet 
L = mvr
L = mr²w
