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Darina [25.2K]
3 years ago
10

How can you tell when an object changes direction on a displacement vs. time graph

Physics
1 answer:
adoni [48]3 years ago
7 0

Answer:

You can see it looking at the slope of the curve.

Explanation:

The slope of the curve its displacement / time, so its the celerity of the object. Now, when the object change direction of its movement, its must change the direction on which its moving, by definition. So, if the object is first getting away from its starting position, you will see its displacement grow, and the slope will be positive (or negative, it depends of the direction you put an positive displacement) Now, when its change position, the displacement will start to shrink, and the slope of the curve will be negative (or positive). To find out the exact moment in which the object changes direction, you can just look at when the slope its equal to zero. If the slope goes from positive to negative, or viceversa, it must pass by zero, the exact momento the object change direction.

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How far can a person run in 15 seconds if she runs at an average speed of 160 cm/s? State your answer in meters.
uysha [10]

Answer: distance = 24 meters

Explanation:

speed = distance / time

distance = speed x time

speed = 160 cm/s = 1.6 m /s     [ 100 cm = 1 m, 160 cm = 1.6 m ]

time = 15 s

distance = 1.6 m/s x 15 s = 24 m

8 0
3 years ago
A cart moves along a track at a velocity of 3.5 cm/s. When a force is applied to the cart, its velocity increases to 8.2 cm/s. I
Lorico [155]

Answer:

3.13cm/s²

Explanation:

Given

Initial velocity u = 3.5cm/s

Final velocity v = 8.2cm/s

Time t = 1.5secs

Required

Acceleration of the cart a

To get that, we will use the equation of motion

v = u+at

Substitute the given parameters

8.2 = 3.5+1.5a

1.5a = 8.2-3.5

1.5a = 4.7

a = 4.7/1.5

a = 3.13cm/s²

Hence the acceleration to the cart is 3.13cm/s²

3 0
3 years ago
In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
Novay_Z [31]

Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

a = 809.82m / 8016s² = 0.101 m/s²

8 0
3 years ago
State pascal is law.<br>please answer me​
Angelina_Jolie [31]

Answer:

Pascal's law says that pressure applied to an enclosed fluid will be transmitted without a change in magnitude to every point of the fluid and to the walls of the container. The pressure at any point in the fluid is equal in all directions

5 0
3 years ago
What is the current through a wire if 240 coulombs of charge pass through the wire in 2.0 minutes?
xenn [34]
Current = charge/time = 240/2x120 =1A.
Current flowing is 1 ampere. 
4 0
3 years ago
Read 2 more answers
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