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BARSIC [14]
3 years ago
6

create a formula giving the strength of the induced field (B) i terms of current (I) and the distance from the wire to the probe

(d)
Physics
1 answer:
iren [92.7K]3 years ago
6 0
So we need to find the formula for magnetic field B using the current (I) and the distance from the probe (d). So, We know that the stronger the current I, the stronger the magnetic field B. That tells us that the I and B are proportional. Also we know that the strength of the magnetic field B is weaker as the distance d of the probe increases. That tells us that B and d are inversely proportional. So our formula should have B=(I/d)*c where c is a constant of proportionality. c=μ₀/2π where μ₀ is the permeability of free space. So finally our formula is B=(μ₀I)/(2πd). 
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Answer the question fast please​
AnnZ [28]

Answer:

1

Explanation:

d = m \div v  \\ m = 0.8 \: v = 80\% \: also \: 0.8 \\ d = 0.8 \div 0.8 \\ d = 1

6 0
3 years ago
Which vector is the sum of the vectors shown below?
qaws [65]
Where is the picture??
4 0
3 years ago
How far did a car travel if it was on the road for 55.2s and it traveled at an average speed of 55m/s
pantera1 [17]
The car traveled 1.00363 kilometers in the 55.2s and the speed of 55m/s
3 0
3 years ago
An airplane is at rest on a runway. It accelerates at 10 m/s2 for 15 seconds. How fast is it now traveling?​
KATRIN_1 [288]

Answer:

150

Explanation:

v = at

v = 10(15)

v = 150 m/s

6 0
3 years ago
In a science museum, a 110 kg brass pendulum bob swings at the end of a 13.9 m -long wire. the pendulum is started at exactly 8:
saw5 [17]

The number of oscillations completed by the pendulum is 2736.

The amplitude of the pendulum is 3.47 m.

The given motion is an underdamped motion. So its frequency will be similar to that of a simple harmonic motion.

The frequency of oscillation is defined as the number of oscillations completed in unit time. It is calculated using the formula.

f=(1/2π)*√(l/g)

where f is the frequency, l is the length of the pendulum, and g is the acceleration due to gravity.

Given the length of the wire l=13.9 m and acceleration due to gravity g=9.8 m/s^2. The frequency of oscillation is:

f=(1/(2*3.14)) * √(13.9/9.8)

f=0.19 Hz (approximately)

Since the pendulum started oscillating at 8:00 am, 4 hours has been passed when it shows 12:00 pm. So time t=4 hours or t=4*3600. Hence t=14400 s. The total number of oscillations is then given by the formula,

n=ft

where n is the number of oscillations.

n=0.19*14400=2736.

In damping motion, the amplitude of the pendulum decreases with time. The amplitude of the pendulum is given by the formula,

A' = A exp (-b*t)

where A' is the amplitude after time t, A is the initial amplitude, b is the damping constant, and t is the time.

Here A=1.2 m, b=0.010 kg/s and t=14400 s.

A' = 1.2 exp (-0.010*14400)

A'=3.47 m (approximately)

Learn more about amplitude.

brainly.com/question/21632362

#SPJ4

5 0
2 years ago
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