What would be the magnitude of an earthquake 100 km away that produced 100 mm of amplitude
2 answers:
You might be interested in
Answer:
velocity = 62.89 m/s in 58 degree measured from the x-axis
Explanation:
Relevant information:
Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.
Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.
Before collision Momentum of A = 1000 x 100 = kg - m/s in the right direction.
Before collision Momentum of B = 2000 x 80 = 1.6 x kg - m/s in upward direction.
Mass of System of after collision = 1000 + 2000 = 3000 kg
Now applying the Momentum Conservation, we get
Initial momentum in right direction = final momentum in right direction =
And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x
So, =
m/s
and m/s
Therefore, velocity is =
=
= 62.89 m/s
And direction is
tan θ = = 1.6
therefore,
= from x-axis
Answer:
<em>The force is now 9 times the original force</em>
Explanation:
<u>Coulomb's Law </u>
The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Coulomb's formula is:
Where:
q1, q2 = the particles' charge
d= The distance between the particles
Suppose the distance is reduced to d'=d/3, the new force F' is:
The force is now 9 times the original force