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ElenaW [278]
3 years ago
11

What would be the magnitude of an earthquake 100 km away that produced 100 mm of amplitude

Physics
2 answers:
Masteriza [31]3 years ago
6 0

Answer: 100000000

Explanation:

erastovalidia [21]3 years ago
3 0
100000000 mark me brainliest and i will thanks you and rate you5

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Which is the correct order of the academic pathway of a pulmonologist?
saul85 [17]

Answer:

B

Explanation:

on edge 2021

6 0
3 years ago
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A 1kg mass is thrown to a height of 2cm. what is the potential energy​
prohojiy [21]
  • Mass=m=1kg
  • Height=h=2cm=0.02m
  • Acceleration due to gravity=g=10m/s^2

\\ \tt\hookrightarrow P.E=mgh

\\ \tt\hookrightarrow PE=1(10)(0.02)

\\ \tt\hookrightarrow PE=0.2J

4 0
2 years ago
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An egg is thrown upward with a velocity of 4.5 m/s. How long will it take to reach it's maximum height?
Ray Of Light [21]

Answer:

0.45 seconds

Explanation:

Letting the value of g = 10 m/s/s

final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)

initial velocity(u) = 4.5 m/s

acceleration = -10 m/s/s (since the gravity is acting against the egg)

time = t seconds

From the first equation of motion:

<em>v = u + at</em>

<em>0 = 4.5 + (-10)t</em>

<em>t = -4.5 / -10</em>

t = 0.45 seconds

3 0
3 years ago
North America experienced all of the following during the last glacial period EXCEPT alpine glaciers covered the Rocky and Casca
Juli2301 [7.4K]

Answer:

the Hudson Bay was covered with alpine glaciers

Explanation:

During the last glacial period, large portions of North America were covered with ice. The majority of the ice was from the ice sheets that were covering Canada and the northern part of the United States, and the alpine glaciers on the mountain ranges. Hudson Bay was all frozen at this point of time. It was not covered with alpine glaciers though, instead it was covered with the ice of the extended ice sheets, with the ice cover reaching up to 2 km in thickness.

5 0
3 years ago
A motorist driving at 25 meters/second decelerates to
Ilia_Sergeevich [38]
Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.

Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,

Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules

Just ignore the negative value for the final result because work is a scalar quantity.
8 0
3 years ago
Read 2 more answers
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