Answer:
K.E₂ = mg(h - 2R)
Explanation:
The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:
K.E₁ + P.E₁ = K.E₂ + P.E₂
where,
K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)
P.E₁ = Initial Potential Energy = mgh
K.E₂ = Final Kinetic Energy at the top of the loop = ?
P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)
Therefore,
0 + mgh = K.E₂ + mg(2R)
<u>K.E₂ = mg(h - 2R)</u>
Answer:
no
Explanation:
this is because its valency shell is full so it wont want any other electrons in its valence shell.
this process is called parellelogram method of resolving vectors.
The final velocity before takeoff is 104.96 m / s.
<u>Explanation:</u>
The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.
To calculate the final velocity,
V = u + at
where v represents the final velocity,
u represents the initial velocity,
a represents the acceleration
t represents the time taken.
v = 104.96 m / s.
Answer:
Substance Y
Explanation:
A substance with a high specific heat capacity can absorb a large quantity of heat before it will raise in temperature. A substance with a low specific heat requires relatively little heat to raise its temperature. Thus, if the same amount of energy was added to both substances, substance Y will reach the higher temperature, while substance X would require more energy to reach high temperatures.
