a) 0.26 h
b) 71.4 km
Explanation:
a)
In order to solve the problem, we have to know what is the final velocity of the car.
Here, we assume that the final velocity reached by the car is
Therefore, we can find the time taken by the car to reach this velocity by using the suvat equation:
where:
u = 250 km/h is the initial velocity
is the acceleration of the car
v = 300 km/h is the final velocity
t is the time
Solving for t, we find:
b)
In order to find the distance covered by the car, we can use the following suvat equation:
where:
s is the distance covered
u is the initial velocity
a is the acceleration
t is the time
For the car in this problem, we have:
u = 250 km/h
t = 0.26 h (calculated in part a)
Therefore, the distance covered is
Answer:
The correct answer is;
The magnitude of the force is 35.12 N
Explanation:
To solve the question, we note that the friction is zero and the force causes motion of a stationary mass
One of the equations of motion is required such as
v² = u² + 2× a× s
Where
v = Final velocity = 5.93 m/s
u = Initial velocity = 0 m/s , object at rest
a = acceleration
s = distance moved = 32 meters
But v = Distance/Time = 32 m /5.4 s = 5.93 m/s
Therefore
5.93² = 2×a×32
or a = 35.12/ 64 = 0.55 m/s²
Therefore Force F = Mass m × Acceleration a
Where mass m = 64 kg
Therefore F = 64 kg×0.55 m/s² = 35.12 N
Answer:962 hz
Explanation: got it right on acellus
Answer:
135°.
Explanation:
R = 75 ohm, L = 0.01 H, C = 4 micro F = 4 x 10^-6 F
Frequency is equal to the half of resonant frequency.
Let f0 be the resonant frequency.
f0 = 796.2 Hz
f = f0 / 2 = 398.1 Hz
So, XL = 2 x 3.14 x f x L = 2 x 3.14 x 398.1 x 0.01 = 25 ohm
Xc = 100 ohm
tan Ф = (25 - 100) / 75 = - 1
Ф = 135°
Thus, the phase difference is 135°.
